2. A skydiver dropped a block of wood at the same time she dove out of the plane. The skydiver has a mass of 85 kg and the block 15 kg. After falling 10 m, the block and the skydiver have the same speed (we are neglecting air resistance while the parachute has not been used). The skydiver then opens her parachute and, 10 additional meters later, the skydiver is moving at 16 m/s. a. How much faster is the block than the skydiver in this final state? b. How much energy was lost by the skydiver due to friction during these last 10 meters? c. Calculate the average air resistance (force) exerted on the skydiver.

2. A skydiver dropped a block of wood at the same time she dove out of the plane. The skydiver has a mass of 85 kg and the block 15 kg. After falling 10 m, the block and the skydiver have the same speed (we are neglecting air resistance while the parachute has not been used). The skydiver then opens her parachute and, 10 additional meters later, the skydiver is moving at 16 m/s. a. How much faster is the block than the skydiver in this final state? b. How much energy was lost by the skydiver due to friction during these last 10 meters? c. Calculate the average air resistance (force) exerted on the skydiver.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

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2. A skydiver dropped a block of wood at the same time she dove out of the plane. The
skydiver has a mass of 85 kg and the block 15 kg. After falling 10 m, the block and the
skydiver have the same speed (we are neglecting air resistance while the parachute has
not been used). The skydiver then opens her parachute and, 10 additional meters later,
the skydiver is moving at 16 m/s.
a. How much faster is the block than the skydiver in this final state?
b. How much energy was lost by the skydiver due to friction during these last 10
meters?
c. Calculate the average air resistance (force) exerted on the skydiver.
makydiver
= 85 kg
miock" 15 kg
A
Vaydiver = Valock = 0
air
10 m
skydiver
block
B
Earth's
field
skydiver block
10 m
16 m/s = v
skydiver
Vtiock
Part a:
E,
E, E,
Ega = Ega + E,
mgh, = mgh, + ½ mv
gh, = gh, + % ?
(10)(20) = (10)(10) + ½ ?
200 = 100 + ½
100 = ½
200 = v2
v = 14.1 m/s
g.8
block
air
Earth
A
в
So the block is moving 1.9
m/s faster than the skydiver!

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