2. A seam has 4 rivets that are defective independently of one another. The probability that any one rivet is defective is 1%. a. List the sample space (or draw a probability tree) for all possible seams using D for defective and N for nondefective for each rivet. (Hint: s has 16 sample polnts.) NODD ZNNNN, NNND, NN DN,NN DP, NONN, NOND ND PN DN ONNO, DN DNN, DN DD DDNN, DD ND, DDE ODDD b. Are all outcomes in Sequally likely? Explain why or why not. the -proba bilby lof defecdive ond NON be cause No. are diferent ir Hr C. Find the probability that 3 rivets are defective. P(3 de fed: ves): Y* PCD)°• p(N. 4*or *M*,0 .0.0000396 d. Define a random variable Y to be the number of defective rivets in a seam. Find a probability mass function for Y. e. Find the cumulative distribution function for Y. Find the expected number of defective rivets in a seam.

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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2. A seam has 4 rivets that are defective independently of one another. The probability that any
one rivet is defective is 1%.
a.
List the sample space (or draw a probability tree) for all possible seams using D for
defective and N for nondefective for each rivet. (Hint: S has 16 sample polnts.)
NODD
NNND, NNDN, NN DP, NONN, NOND ND PN ONNN)
ONNO, DN DN, ON DD DDNN, DD ND, DODN
ODDD
b.
Are all outcomes in S equally likely? Explain why or why not.
because the proba b.lby of defledive ond
NON. doffer
No.
ane diferent fr
C.
Find the probability that 3 rivets are defective.
3.
P(3 de feo: ves): 4* PCD)°• p. 4*or *** .99
.0.0000396
d. Define a random variable Y to be the number of defective rivets in a seam. Find a
probability mass function for Y.
e. Find the cumulative distribution function for Y.
| Find the expected number of defective rivets in a seam.
just parts de and f
Transcribed Image Text:2. A seam has 4 rivets that are defective independently of one another. The probability that any one rivet is defective is 1%. a. List the sample space (or draw a probability tree) for all possible seams using D for defective and N for nondefective for each rivet. (Hint: S has 16 sample polnts.) NODD NNND, NNDN, NN DP, NONN, NOND ND PN ONNN) ONNO, DN DN, ON DD DDNN, DD ND, DODN ODDD b. Are all outcomes in S equally likely? Explain why or why not. because the proba b.lby of defledive ond NON. doffer No. ane diferent fr C. Find the probability that 3 rivets are defective. 3. P(3 de feo: ves): 4* PCD)°• p. 4*or *** .99 .0.0000396 d. Define a random variable Y to be the number of defective rivets in a seam. Find a probability mass function for Y. e. Find the cumulative distribution function for Y. | Find the expected number of defective rivets in a seam. just parts de and f
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