2. A sample of neon gas is contained in a bulb at 150 °C and 350 kPa. If the pressure drops to 103 kPa, find the new temperature, in degrees Celsius. NOTE: in the video, temperatures are given on the Kelvin scale. If they had been given in degrees Celsius instead, you would have to convert them to the Kelvin scale -- Gay-Lussac's Law does NOT work if the temperatures are in degrees Celsius. P₁ = 350 kPa P2 = 103 kPa T1= 150°C T2=?
2. A sample of neon gas is contained in a bulb at 150 °C and 350 kPa. If the pressure drops to 103 kPa, find the new temperature, in degrees Celsius. NOTE: in the video, temperatures are given on the Kelvin scale. If they had been given in degrees Celsius instead, you would have to convert them to the Kelvin scale -- Gay-Lussac's Law does NOT work if the temperatures are in degrees Celsius. P₁ = 350 kPa P2 = 103 kPa T1= 150°C T2=?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve using gay-lussac’s law.

Transcribed Image Text:2. A sample of neon gas is contained in a bulb at 150 °C and 350 kPa. If the
pressure drops to 103 kPa, find the new temperature, in degrees Celsius.
NOTE: in the video, temperatures are given on the Kelvin scale. If they had been
given in degrees Celsius instead, you would have to convert them to the Kelvin
scale -- Gay-Lussac's Law does NOT work if the temperatures are in degrees
Celsius.
P₁ = 350 kPa
P2= 103 kPa
T1= 150°C
T2=?
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