2. A rectangular beam section is 16 in. wide and has a structural depth of 26 in. Flexural reinforcement consists of three No. 9 bars. Given that the section has No. 3 stirrups at 13 in. spacing, a specified concrete strength of 4000 psi, and fy of 60,000 psi, calculate the factored shear capacity of the section. (5 pt) (Hint: In calculating Vò, a bigger value will be taken from the results of two equations V₁ = 2λ Jribw f'bwd and V₁ = 8λ(pw)¹/³ √f.bwd). b = 16 in d = 26 in λ=1.0 f=4000 psi fyt = 60000 psi
2. A rectangular beam section is 16 in. wide and has a structural depth of 26 in. Flexural reinforcement consists of three No. 9 bars. Given that the section has No. 3 stirrups at 13 in. spacing, a specified concrete strength of 4000 psi, and fy of 60,000 psi, calculate the factored shear capacity of the section. (5 pt) (Hint: In calculating Vò, a bigger value will be taken from the results of two equations V₁ = 2λ Jribw f'bwd and V₁ = 8λ(pw)¹/³ √f.bwd). b = 16 in d = 26 in λ=1.0 f=4000 psi fyt = 60000 psi
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:2. A rectangular beam section is 16 in. wide and has a structural depth of 26 in. Flexural
reinforcement consists of three No. 9 bars. Given that the section has No. 3 stirrups at 13 in.
spacing, a specified concrete strength of 4000 psi, and fy of 60,000 psi, calculate the factored
shear capacity of the section. (5 pt)
(Hint: In calculating Vò, a bigger value will be taken from the results of two equations V₁ = 2λ
Jribw
f'bwd and V₁ = 8λ(pw)¹/³ √f.bwd).
b = 16 in
d = 26 in
λ=1.0
f=4000 psi
fyt = 60000 psi
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