2. A precipitate of Pbl, is formed when 5 mL of 0.012 M Pb(NO,), is added to 5 mL of0.030 M KI. It was found experimentally that the final concentration of I in the 10 mL solution after equilibrium was 8 x 10 M a) How many moles of Pb?* are originally in the solution? b) How many moles of I' are originally present? c) How many moles of I' remained in solution after equilibrium?

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2. A precipitate of Pbl, is formed when 5 mL of 0.012 M Pb(NO,), is added to 5 mL of 0.030 M KI.
It was found experimentally that the final concentration of I in the 10 mL solution after equilibrium
was 8 x 10³M
a) How many moles of Pb?* are originally in the solution?
b) How many moles of I' are originally present?
c) How many moles of I´ remained in solution after equilibrium?
Transcribed Image Text:2. A precipitate of Pbl, is formed when 5 mL of 0.012 M Pb(NO,), is added to 5 mL of 0.030 M KI. It was found experimentally that the final concentration of I in the 10 mL solution after equilibrium was 8 x 10³M a) How many moles of Pb?* are originally in the solution? b) How many moles of I' are originally present? c) How many moles of I´ remained in solution after equilibrium?
Expert Solution
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Concentration of lead nitrate = 0.012M

Volume of lead nitrate = 5mL

 

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