2. A point P moving in a simple harmonic motion makes 10 complete revolutions every 1 sec. The amplitude of the motion is 2 m. Assuming that P is at its minimum displacement with respect to the equilibrium when t = 0 and there is a vertical shift of 2 m downward, find a sine function that describes the path traced by P in terms of time t.
2. A point P moving in a simple harmonic motion makes 10 complete revolutions every 1 sec. The amplitude of the motion is 2 m. Assuming that P is at its minimum displacement with respect to the equilibrium when t = 0 and there is a vertical shift of 2 m downward, find a sine function that describes the path traced by P in terms of time t.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 74E
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Answer the following with complete solution.
![2. A point P moving in a simple harmonic motion makes 10 complete revolutions every 1
sec. The amplitude of the motion is 2 m. Assuming that P is at its minimum
displacement with respect to the equilibrium when t = 0 and there is a vertical shift
of 2 m downward, find a sine function that describes the path traced by P in terms of
time t.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb93d5619-64db-46fe-9e63-226c9ccfb1a3%2F82b02ed4-bd21-4d4d-87aa-7adb1f52f8fc%2Fezb2lef_processed.png&w=3840&q=75)
Transcribed Image Text:2. A point P moving in a simple harmonic motion makes 10 complete revolutions every 1
sec. The amplitude of the motion is 2 m. Assuming that P is at its minimum
displacement with respect to the equilibrium when t = 0 and there is a vertical shift
of 2 m downward, find a sine function that describes the path traced by P in terms of
time t.
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