2. A plot of In K vs. gives a slope of -2980 K and an intercept of -10.6. Calculate7/AH° in kJ/mol and AS° in J-K-¹·mol-¹. Hint: What is the equation for this line interms of K, T, AH° and AS°?

Answered: Image /qna-images/answer/ef8603cf-d8fd-4d1a-8eea-37a1704f0a69.jpg

2. A plot of ln K vs. gives a a slope of -2980 K and an intercept of -10.6. Calculate AH° in kJ/mol and AS° in J-K-¹-mol-¹. Hint: What is the equation for this line in terms of K, T, AH° and AS°?

2. A plot of ln K vs. gives a a slope of -2980 K and an intercept of -10.6. Calculate AH° in kJ/mol and AS° in J-K-¹-mol-¹. Hint: What is the equation for this line in terms of K, T, AH° and AS°?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: Consider the following system at equilibrium where AH° = -16.1 kJ, and K = 154, at 298 K. 2NO(g) +…

Q: Consider the reaction CS, (9) + 4H2 (9) = CH, (g) + 2H,S(9) a. Calculate AH°, AS", and AG" at 25°C…

Q: Consider the reaction: CO(g) + 2 H2(3) = CH;OH(g) Kp = 2.26 x 104ʻat 25 °C Calculate AGan for the…

A: (a) Standard conditions: ΔG°rxn = -2.303 RT log K = - 2.303 x 8.314 x 298 log (2.26 x…

Q: a Calculate AH° for the reaction 2K(s) + 2H20(1) → 2KOH(aq) +H2 (g) Substance and State AH (kJ/mol)…

A: Mass of water given = 1000 gram Molar mass of water = 18 g/mol

Q: to access important values if needed for this question. Consider the following system at equilibrium…

A: If the volume of a gaseous reaction is decreased, the pressure exerted by the molecules will…

Q: Determine AG° for a reaction when AG = -127.0 kJ/mol and Q = 0.043 at 298 K. (R = 8.314 J/mol K)…

A: The correct answer is given below

Q: [13] The following pictures represent the composition of the equilibrium mixture for the reaction, A…

A: Given:Reaction;For picture 1Temperature = 298 KFor picture 2Temperature = 310 KDetermine the sign of…

Q: Calculate AG for the reaction given below if the partial pressure of NO₂ is 0.220 atm and the…

A: This is simple problem of chemical equilibrium where we have to determine if the reaction is in…

Q: NO + O2 NO2 for which H° = –57.03 kJ and K = 1.46 106 at 25°C.a. Calculate H° at 25°C for…

A: Since we are entitled to answer up to 3 sub-parts, we’ll answer the first 3 as you have not…

Q: Determine K for a reaction at 200 K if AG° =22.8 kJ/mol. (R = 8.314 J/mol · K)

A: Given is ΔG° = 22.8 kJ/mol = 22800 J/mol T = 298 K R = 8.314 J/mol-K We are to find the equilibrium…

Q: Consider the following system at equilibrium where K. = 5.10×10-0 and AH° = 268 kJ/mol at 548 K. %3D…

A: From the given data 1) True Justification: The value ∆H° for a forward reaction that is…

Q: Ag2CO3 (s) 2Ag+(aq) + CO3-2 (aq) G= -64.88J/mol b. CaF2(s) Ca+2(aq) + 2F-(aq) G= -59.32J/mol…

A: From the reaction between equilibrium constant and Gibbs free energy change is □G = - RT × ln(K)…

Q: e AG° f

Q: Consider the following system at equilibrium where AH° = 111 kJ, and K, = 6.30, at 723 K. 2NH3(g)…

A: When a reaction proceeds in both forward and backward directions, such reactions are called…

Q: Calculate AG for the reaction given below if the partial pressure of NO2 is 0.273 atm and the…

Q: For each of the following reactions at constant temperature, predict whether ArS is positive or…

Q: Consider the following system at equilibrium where AH = -87.9 kJ, and K = 83.3, at 5.00 × 10² K:…

A: Given: ∆H° = -87.9 KJKc = 83.3 T = 5.00 × 102 KLe Chateliar' principle: A reaction at equilibrium…

Q: Consider the following system at equilibrium where AH° = -111 kJ/mol, and Kc = 0.159, at 723 K. N₂…

Q: LU dCcess important values if needed for this question. Consider the following system at equilibrium…

Q: Consider the following equilibrium: 2NO, (g) -N,04(g) AG" = - 5.4 kJ Now suppose a reaction vessel…

A: According to Le Chatelier principle, if a system is subjected to stress by changing…

Q: For a given reaction with AH = -28.1 kJ/mol, the AG=0 at 372 K. The value of AS must be --------…

A: ∆H = -28.1 kJ/mol∆G = 0T = 372 K∆S = ?

Q: At 298 K, AH° is 66.4 kJ/mol and As° is 26.9 J/mol K. What is AG° for this reaction at this…

A: Given data, the temperature (T) = 298 K enthalpy changes (∆Ho) = 66.4 kJ/mol entropy changes (∆So) =…

Q: ol. What is the ratio of the equilibrium constant at 400 K to that at 200 K?

Q: 2. Čalculate Kp at 208 K for the reaction SO,g) + NO,(e) S S0;e) + NO(g). + NO(g). www AG°? -300.4…

A: The standard free energy change for the reaction can be calculated as:…

Q: What is K for a reaction if /\G° =-178.6 kJ/mol at 25 °C (or 298 K)? (R = 8.314 J/mol • K)

A: Information of question

Q: Determine AG° for the reaction 3 N,(g) + 2 O,(g) → 6 NO(g) at 223°C. kJ/mol AH° = +257.7 kJ/mol 1 3.…

Q: The equilibrium constant for a reaction is 0.599 at 25C. What is the value of delta G for this…

A: The value of free energy at 25°C is related to the equilibrium constant as ∆G°=-RTlnK where…

Q: The AG for the following reaction at equilibrium is 212 kJ. Calculate K for the reaction at 25°C.…

Q: this aprt of calculation seems wrong ΔG° = -RTln(K) =>-3.9 × 10^5 J/Mol. = - 8.314 J/K .Mol ×…

A: The standard Gibbs free energy change is ∆G0 = -3.9×105 J/mol. The temperature is T = 298 K. We have…

Q: NH3(g) + HCI(g) = NH,CI(s) Calculate the equilibrium constant for this reaction at 298.15 K.…

Q: Given the standard heats of formation for the following compounds, calculate AH of the reaction at…

A: The enthalpy change of a reaction can be calculated from enthalpies of formation of reactants and…

Q: 18)The AG, of atomic oxygen (for one O atom) is 230.1 kJ/mol and that for 0, is zero kJ/mol.…

A: ∆G°rxn = 2 x ∆G°(O,g) - 1x ∆G°(O2,g) ∆G°rxn = 2 x 230.1 - 1 x 0 ∆G°rxn = 460.2 KJ

Q: Consider the following system at equilibrium where AH° = 87.9 kJ, and K. = 1.20×10-2, at 500 K.…

A: Kc only change when we change temperature . Hence value of Kc remain the same . As we increase the…

Q: What is K for a reaction if AG° =-217.3 kJ/mol at 25 °C (or 298 K)? (R = 8.314 J/mol · K) .

Q: For the reaction 2H,S(g) + 302(g)– 2H,0(g) + 2S02(g) AH° = -1.04x103 kJ and AS° = -153 J/K %3D The…

Q: 1. Predict the sign for AS° and then calculate AS° and AH° from the data in appendix. CO(g) + 2H2(g)…

A: The balanced chemical eqution: CO (g) + 2 H2 (g) ⇔CH3OH (l)

Q: For the reaction 2S02(g) + O2(g)–2SO3(g) AH° = -197.8 kJ and ASº = -187.9 J/K The equilibrium…

A: Given: ∆Ho = -197.8 kJ = -197.8×103 J (Since 1 kJ = 103 J) ∆So = -187.9 J/K Temperature (T) = 271.0…

Q: What is the equilibrium constant for a reaction at 25 °C. The value of AG is - 57.5 kJ/mol. (R-8.315…

A: Gibbs' free energy : It is used to calculate the maximum reversible work that can be done by a…

Q: 7. The equilibrium constant for the reac- tion N2(8) + O2(g) 2NO(g) at 2130°C is 2.5 × 10-3. Why is…

Q: 8. The reaction: 2PCI3() + O2lg)2OPCI3(g) has AH° = -508 kJ-mol-1 and AS° - 178 J-mol-1.K-1, What is…

A: The equation is, ∆Go=∆Ho-T∆So∆Go=gibb's free energy∆Ho=Enthalpy changeT =Temperature∆So=Entropy…

Q: Consider the gas phase reaction NO + %02=NO2 for which AH° = -57.05 kJ and K= 1.54 × 10° at 25°C.…

A: According to ideal gas law, PV = nRT where P = pressure V = volume n = moles R = gas constant T =…

Q: The equilibrium constant, Kp, for the following reaction is 2.01 at 500 K. PCl3(g) + Cl₂(g) PCI,(g)…

A: We have T1 = 500 KT2 = 589 Kk1 = 2.01k2 = ?ΔH = -87.9 kJ

Q: The change in enthalpy (AH) for a reaction is 34.4 kJ/mol. The equilbrium constant for the reaction…

Q: what temperature, in °C, is a certain reaction at equilibrium if AH = 3.8 kJ/mol and AS = +170.2…

A: At equilibrium change in Gibbs free energy is equal to zero

Q: 2) a)Determine AGrxn° values for the following Combustion reactions at 25°C b) Decide whether this…

A: We have to find ∆G of reaction, and we have to tell whether reaction is spontaneous or not.

Q: Consider the following system at equilibrium where AH° = -10.4 kJ, and K. 55.6, at 698 K. %3D H2(9)…

A: Given: Kc for the reaction = 55.6

Q: Consider the following system at equilibrium where K̟ = 154 and AH° = -16.1 kJ/mol at 298 K. 2 NO…

Q: wribe out the balanced Chemical equation (with subscripts) and include energy b)If were to maximile…

A: Given: Haber process is exothermic To Find: 1. Balanced chemical reaction 2. To maximize the…

Q: a) For a reaction with AH = -152.6 kJ mol-¹ and AS° = -543.8 J K-¹ mol-¹ at 25 °C, how will AG⁰…

Question

2. A plot of In K vs. gives a slope of -2980 K and an intercept of -10.6. Calculate
7/
AH° in kJ/mol and AS° in J-K-¹·mol-¹. Hint: What is the equation for this line in
terms of K, T, AH° and AS°?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

Calculate AG° for the reaction shown below using the provided thermodynamic properties information. H2O2 (1) → 2 H2O () + O2 (g) Substance AH°; (kJ/mol) AS° (J/(mol•K)) H2O2 (1) - 187.8 232.9 H20 (1) -285.83 69.91 O2 (g) 205.0 -396.4 kJ/mol -350.5 kJ/mol -33.70 kJ/mol -1105 kJ/mol -417.2 kJ/mol
For reaction of A and B: A + B C , rHo = -20 kJ mol-1 and K = 50 at 25C. Calculate K at 100 C.
At -5.92 °C the pressure equilibrium constant K = 5.9 for a certain reaction. P Here are some facts about the reaction: • If the reaction is run at constant pressure, 127. kJ/mol of heat are released. • The constant pressure molar heat capacity C • The net change in moles of gases is -1. = 2.41 J mol -1. K¹. -1 р Yes. ☐ x10 Using these facts, can you calculate K at -27. °C? ○ No. If you said yes, then enter your answer at right. Round it to 2 significant digits. Р If you said no, can you at least decide whether K at -27. °C will be bigger or smaller than K, at −5.92 °C? П Yes, and K, will be р bigger. Yes, and K smaller. will be No. ☑
Consider the following system at equilibrium where AH° = -87.9 kJ, and K. = 83.3, at 500 K. PC13(g) + Cl2(g) =PCI5(g) When 0.31 moles of Cl2(g) are removed from the equilibrium system at constant temperature: The value of K. increase. decrease. remain the same. The value of Qc K.. is greater than is equal to is less than The reaction must Orun in the forward direction to restablish equilibrium. Orun in the reverse direction to restablish equilibrium. Oremain the same. It is already at equilibrium. The concentration of PC13 will increase. decrease. remain the same.
Given the dissociation of methane to graphite (C) and hydrogen gas. For the methane at 298K, Given the following data: kJ = -74.85- mol = -80.67 mol · K A,GE.graphite = A,Gån = 0 %3D Solve the following: a. Calculate the equilibrium constant (K) of the dissociation of methane at 298K with the appropriate units. b. Assuming that enthalpy is independent of temperature, Calculate the equilibrium constant (K) of methane dissociation at 1000 K. C. Calculate the ratio between the amounts of methane and hydrogen gas at 298 K and 0.2 bar.
Consider the following system at equilibrium where AH° = -111 kJ, and K. = 0.159, at 723 K. N2(g) + 3H2(g)=2NH3(g) If the VOLUME of the equilibrium system is suddenly decreased at constant temperature: The value of K. A. increases. B. decreases. C. remains the same. The value of Qe |A. is greater than Kç. B. is equal to Ke. C. is less than K. ]A. run in the forward direction to reestablish equilibrium. The reaction must: B. run in the reverse direction to reestablish equilibrium. C. remain the same. It is already at equilibrium. The number of moles of H2 will: | A. increase. B. decrease. C. remain the same.
The equilibrium constant for a certain reaction decreases from 8.87 to 3.25 x 10-2 when the temperature increases from 25°C to 75°C. Hint: Manipulate the following equation. In(K) = -AH° ASO + ᎡᏆ R a Estimate the value of AS° for this reaction. AS⁰ = J/K - mol
18. Given the AG°S for the reactions, calculate Ks. Values given for 298 K AG° -560.3 kJ 2 H2(g) a. CH4(g)+2 F2(g) 4(g) 2 NO)Cl2(g) 2 SO3() AG° +40.8 kJ b. 2 NOC (g) AG° = -140.0 kJ c. 2 SO2(g) O2(g)
[References] Use the References to access important values if needed for this question. Consider the following system at equilibrium where AH° = 16.1 kJ, and Kc = 6.50 x 10-3, at 298 K: 2NOBr(g) 2NO(g) + Br₂(g) If the VOLUME on the equilibrium system is suddenly increased at constant temperature: The value of Ke Oincreases O decreases O remains the same The value of Qc O is greater than Ke O is equal to Ke O is less than K The reaction must run in the forward direction to reestablish equilibrium. Orun in the reverse direction to reestablish equilibrium. Oremain the same. It is already at equilibrium. The number of moles of Br2 will O increase O decrease O remain the same Show Hint F5 6 H F6 & 7 KI F7 * 8 DII F8 ( 9 DD F9 ) O F10 P F11 Previous + Next Save and Exit F12 delete
Consider the following system at equilibrium where K. = 34.5 and AH° = -198 kJ/mol at 1150 K. 2 So, (g) + 02 (g) =2 S03 (g) The production of S03 (g) is favored by: Indicate True (T) or False (F) for each of the following: ]1. decreasing the temperature. v 2. increasing the pressure (by changing the volume). | 3. decreasing the volume. 4. removing SO3 . 5. removing O2 -
9. The K, value of the reaction N₂04 2NO, is 0.113. What is the Gibbs free energy, AG, of the reaction if the initial pressure of N₂O4 is 1.23 atm while NO₂ is 0.750 atm? Is the process spontaneous? 10. The molar heat of vaporization of ammonia is 23.4 kJ/mol while its boiling point is -33.34 °C. Calculate the AS for the vaporization of 0.75 moles of ammonia. Express your answer with unit J/K.
:Calculate Kp for the following reaction.5 A(g) = 2 B(g) + C(g) 2 .at 400 °C if Kc at 400 °C for this reaction is 0.15 * (R = 8.314 J/mol.K = 0.0821 L.atm/mol.K) %3D 8 0 41 O 30 O 19 O 53 O