2. A platform edge section of a uniform chain of length 8 ft is loosely wound around a peg at the edge of a high horizontal platform, and the remaining part of the chain hangs still on the edge of the platform. The length of the extended chain is 3 ft, the chain weighs 2 Ib/ft, and the positive direction is downwards. Starting at t= 0 seconds, the weight of the outstretched part causes the chain on the table to slip smoothly and fall to the floor. If x(t) represents the length of the chain protruding into the table at timet = 0, then v = dx/dt is the velocity. When all resistive
2. A platform edge section of a uniform chain of length 8 ft is loosely wound around a peg at the edge of a high horizontal platform, and the remaining part of the chain hangs still on the edge of the platform. The length of the extended chain is 3 ft, the chain weighs 2 Ib/ft, and the positive direction is downwards. Starting at t= 0 seconds, the weight of the outstretched part causes the chain on the table to slip smoothly and fall to the floor. If x(t) represents the length of the chain protruding into the table at timet = 0, then v = dx/dt is the velocity. When all resistive
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:2. A
platform edge
x(1)
section of a uniform chain of length 8 ft is loosely wound around a peg at the edge of a high
horizontal platform, and the remaining part of the chain hangs still on the edge of the
platform. The length of the extended chain is 3 ft, the chain weighs 2 Ib/ft, and the positive
direction is downwards. Starting at t = 0 seconds, the weight of the outstretched part causes
the chain on the table to slip smoothly and fall to the floor. If x(t) represents the length of the
chain protruding into the table at time t = 0, then v = dx/dt is the velocity. When all resistive
forces are neglected, it can be shown that the mathematical model relating v to x is:
dv
XV-+ v2 = 32x
dx
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