2. A pilot flying a helicopter locates a person on the ground. The horizontal distance from the person to the helicopter and the height of the helicopter above the person are shown in the diagram. Helicopter 500 ft Person. -950 ft- What is the approximate angle of elevation from the person to the helicopter? (A) 28° (C) 58° (B) 32° (D) 62°
2. A pilot flying a helicopter locates a person on the ground. The horizontal distance from the person to the helicopter and the height of the helicopter above the person are shown in the diagram. Helicopter 500 ft Person. -950 ft- What is the approximate angle of elevation from the person to the helicopter? (A) 28° (C) 58° (B) 32° (D) 62°
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![### Problem Statement
A pilot flying a helicopter locates a person on the ground. The horizontal distance from the person to the helicopter and the height of the helicopter above the person are shown in the diagram.
---
**Diagram:**
- A line segment labeled "Person" on the left extending horizontally 950 ft to the right.
- A vertical line segment labeled "Helicopter" on the right, extending upward 500 ft.
- The right-angle triangle formed by these segments represents the relationship between the person on the ground and the helicopter above them.
---
**Question:**
What is the approximate angle of elevation from the person to the helicopter?
**Choices:**
A. 28°
B. 32°
C. 58°
D. 62°
---
### Explanation:
This problem involves basic trigonometry. The angle of elevation can be found using the tangent function, which is the ratio of the opposite side (height of the helicopter) to the adjacent side (horizontal distance from the person to the helicopter).
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{500 \text{ ft}}{950 \text{ ft}} \]
Solving for \( \theta \) will give us the angle of elevation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4495d839-413a-4bf2-bcb4-555f6e03b467%2F746e4928-93bf-488a-b62d-510e7d640265%2Fa25gjal_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Statement
A pilot flying a helicopter locates a person on the ground. The horizontal distance from the person to the helicopter and the height of the helicopter above the person are shown in the diagram.
---
**Diagram:**
- A line segment labeled "Person" on the left extending horizontally 950 ft to the right.
- A vertical line segment labeled "Helicopter" on the right, extending upward 500 ft.
- The right-angle triangle formed by these segments represents the relationship between the person on the ground and the helicopter above them.
---
**Question:**
What is the approximate angle of elevation from the person to the helicopter?
**Choices:**
A. 28°
B. 32°
C. 58°
D. 62°
---
### Explanation:
This problem involves basic trigonometry. The angle of elevation can be found using the tangent function, which is the ratio of the opposite side (height of the helicopter) to the adjacent side (horizontal distance from the person to the helicopter).
\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{500 \text{ ft}}{950 \text{ ft}} \]
Solving for \( \theta \) will give us the angle of elevation.
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