2. A particle is moving along a straight line with the acceleration a=(12t-3(t^1/2)) ft/s^2, where t is in seconds. Determine the velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft. 4 Ans. y = (6r² – 2r2)ft/s i s - (2 - + 15 )n 2t - 5/2
2. A particle is moving along a straight line with the acceleration a=(12t-3(t^1/2)) ft/s^2, where t is in seconds. Determine the velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft. 4 Ans. y = (6r² – 2r2)ft/s i s - (2 - + 15 )n 2t - 5/2
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
Transcribed Image Text:2. A particle is moving along a straight line with the acceleration a=(12t-3(t^l/2)) ft/s^2, where t is in seconds. Determine the
velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft.
(6? – 21/2)ft/s ; s =
2t
Ans.
v =
+ 15 )ft
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