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2. A particle is moving along a straight line with the acceleration a=(12t-3(t^1/2)) ft/s^2, where t is in seconds. Determine the velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft. 4 Ans. y = (6r² – 2r2)ft/s i s - (2 - + 15 )n 2t - 5/2

2. A particle is moving along a straight line with the acceleration a=(12t-3(t^1/2)) ft/s^2, where t is in seconds. Determine the velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft. 4 Ans. y = (6r² – 2r2)ft/s i s - (2 - + 15 )n 2t - 5/2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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2. A particle is moving along a straight line with the acceleration a=(12t-3(t^l/2)) ft/s^2, where t is in seconds. Determine the velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft. (6? – 21/2)ft/s ; s = 2t Ans. v = + 15 )ft
Transcribed Image Text:2. A particle is moving along a straight line with the acceleration a=(12t-3(t^l/2)) ft/s^2, where t is in seconds. Determine the velocity and the position of the particle as a function of time. When t = 0, v = 0, s = 15ft. (6? – 21/2)ft/s ; s = 2t Ans. v = + 15 )ft
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