2. A parabola whose focus is at the point (2,0), has a directrix whose equation is x = 6. For this parabola the vertex is no longer at (0,0). Use the equation: (y- k)2 = -4a(x – h) where: h & k are the coordinates of the Vertex, a is the focal length and of course 4a is the Length of the Latus Rectum and x & y are coordinates of a point on the parabola. Find the following: a) The focal length or a. b) The coordinates of the vertex c) The length of the Latus Rectum d) The endpoints of the Latus Rectum e) The equation of the parabola f) Sketch of the Graph including the Directrix

Q: y2 = 20x О А. (5,0), х - -5, у-аxis В. (5,5), х%3D5, х-аxis С. (5,0), х%3D — 5, х-аxis D. (0,5), y…

A: Given query is to find the the focus , directrix and symmetry for the parabola.

Q: Find an equation of the parabola with focus (-2,-5) and directrix y=3

A: NOTE: Refresh your page if you can't see any equations. .

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A: Directrix is a line which together with a point called the focus defines the set of points that form…

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Q: Find an equation for the parabola with focus (0, -4) and directrix y =

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Q: b) Sketch the parabola with the graph cuts the x-axis at (5,0) and (-5,0), the directrix line y = 4…

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Q: graph and find: a. ends of the latus rectum b. equation of the directrix c. equation of the axis…

A: As we know that the standard form of the parabola is: y-k2=4px-h2 vertex: h,kfocal length: p Given:…

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A: As per the guidelines we are supposed to solve one question at a time. Please repost other questions…

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A: The standard form of a parabola is  (x – h)2 = a(y – k) where (h, k) is the vertex.

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Q: Write an equation of the parabola with its vertex at (x, y) - (3, 9) and focus at (x, y) (3,-2).

A: The parabola has vertex at (h,k)= (3, 9) and focus at (h,k+a)= (3, -2) Hence axis of symmetry is x=3…

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A: Here we find the intersecting point of parabola and the line.

Q: Write the equation of the parabola in standard form sati 1. Vertex (1, – 9); Focus (- 3, - 9)

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