2. A parabola whose focus is at the point (2,0), has a directrix whose equation is x = 6. For this parabola the vertex is no longer at (0,0). Use the equation: (y- k)2 = -4a(x – h) where: h & k are the coordinates of the Vertex, a is the focal length and of course 4a is the Length of the Latus Rectum and x & y are coordinates of a point on the parabola. Find the following: a) The focal length or a. b) The coordinates of the vertex c) The length of the Latus Rectum d) The endpoints of the Latus Rectum e) The equation of the parabola f) Sketch of the Graph including the Directrix

Q: y2 = 20x О А. (5,0), х - -5, у-аxis В. (5,5), х%3D5, х-аxis С. (5,0), х%3D — 5, х-аxis D. (0,5), y…

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