2. A DSB-SC AM signal is modulated by the signal m (t) = 2cos2000nt + cos6000nt. The modulated signal is u(t) = 100m(t)cos (2nf.t), where fe = 1 MHz. Determine and sketch the spectrum of the AM signal.“ Answer: 1) The modulated signal is written as u(t) = 100(2 cos(2n103t) + cos(2n × 3 × 10³t)) cos(2nf.t) = 100[cos(2n(fc + 103)t) + cos(27(f. – 103)t)] + 100[cos(2n(fe + 3 x 103)t) + cos(27(fe – 3 x 103)t)]« - - Taking the Fourier transform of the previous expression, we obtain - U(f) = 50[8(f - (fe + 103)) + 8(f + fc + 10³) + 8(f – (fc + 10³)) + 8(f + fc + 10³ )]« + 25[8(f – (fe + 3 x 103)) + 8(f + fc + 3 × 10³) + 8(f – (fc – 3 × 10³)) + 8(f + fc – 3 × 10³)« - The spectrum of the signal is depicted in the next figure |50 25 -1003 -1001 -999 -997 997 999 1001 1003 KHz

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Thermistors

A thermistor is a special type of resistor whose resistance is more temperature-dependent than standard resistors.  The resistance of the thermistor decreases with increasing temperature. This is the basic principle of thermistors. This allows the thermistor circuit to detect very small temperature changes that cannot be observed with the Resistance temperature detectors (RTDs) or the thermocouples. Since the resistance of a thermistor is temperature dependent, it can be connected to an electrical circuit to measure body temperature. This high sensitivity to temperature changes makes thermistors very useful for accurately controlling and calibrating temperature measurements. In general, resistance increases with increasing temperature in most metals, but thermistors react negatively.