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2. A consumer survey indicates that the average household spends µ = $155 on groceries each week. The distribution of spending is approximately normal with a standard deviation of a = $25. Based on this distribution, what proportion of the population spends more than $175 per week on groceries? Hint: This distribution is of X scores not sample means. As a result, think carefully about what you put in your denominator when calculating the z-score.

2. A consumer survey indicates that the average household spends µ = $155 on groceries each week. The distribution of spending is approximately normal with a standard deviation of a = $25. Based on this distribution, what proportion of the population spends more than $175 per week on groceries? Hint: This distribution is of X scores not sample means. As a result, think carefully about what you put in your denominator when calculating the z-score.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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2. A consumer survey indicates that the average household spends µ = $155 on groceries each week. The distribution of spending is approximately normal with a standard deviation of 6 = $25. Based on this distribution, what proportion of the population spends more than $175 per week on groceries? Hint: This distribution is of X scores not sample means. As a result, think carefully about what you put in your denominator when calculating the z-score.
Transcribed Image Text:2. A consumer survey indicates that the average household spends µ = $155 on groceries each week. The distribution of spending is approximately normal with a standard deviation of 6 = $25. Based on this distribution, what proportion of the population spends more than $175 per week on groceries? Hint: This distribution is of X scores not sample means. As a result, think carefully about what you put in your denominator when calculating the z-score.
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