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2. A coach has 6 players that will join track and field. The random vanable that is being studied is X, the number of players that will win. The probability function for this variable is shown in the table below. 1. 2. 3. 4. 5. )-P[X=x] 0.40 0.24 0.19 0.1 0.05 0.02 Question: Find the probability that the majority of the players will win the play? Solution and answer:

2. A coach has 6 players that will join track and field. The random vanable that is being studied is X, the number of players that will win. The probability function for this variable is shown in the table below. 1. 2. 3. 4. 5. )-P[X=x] 0.40 0.24 0.19 0.1 0.05 0.02 Question: Find the probability that the majority of the players will win the play? Solution and answer:

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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1. An investor has five stocks that she follows each day. The random variable being studied is X, the number of stocks that increases in value each day The probability function for this variable is shown below. 1 2 3. 5. f(x)=P[X=x 0.34 .30 20 .10 .05 .01 Question: Find the probability that on a given day, majority of the stocks will increase in value. Solution: Majority of the stocks means we will consider stocks(X) which is minimum more than half from O to 5. Hence, we need to find P[x2 3]. Plx 2 3)= P(x = 3]+ P(x = 4]+ P[x = 5] = /(3) + f(4) +f(5) = (0.10+0.05 +0.01 where Plx > 31 = Plx = 3| + Px= 41 + P[x 5] = (3) + (4) + f(5) = 0.10 + 0.05 +0.01 =0.16 Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%). 2. A coach has 6 players that will join track and field. The random vanable that is being studied is X, the number of players that will win. The probability function for this variable is shown in the table below. 1 3. 4. 0.05 0.02 )= P[X=x] 0.40 0.24 0.19 0.1 Question: Find the probability that the majority of the players will win the play? Solution and answer: 3. A census was conducted at a prison. All prisoners were asked how many tattoos they had which will serve as random vanable X. The table below shows the probability distribution for random variable X. 3 4 'DUCATION
Transcribed Image Text:1. An investor has five stocks that she follows each day. The random variable being studied is X, the number of stocks that increases in value each day The probability function for this variable is shown below. 1 2 3. 5. f(x)=P[X=x 0.34 .30 20 .10 .05 .01 Question: Find the probability that on a given day, majority of the stocks will increase in value. Solution: Majority of the stocks means we will consider stocks(X) which is minimum more than half from O to 5. Hence, we need to find P[x2 3]. Plx 2 3)= P(x = 3]+ P(x = 4]+ P[x = 5] = /(3) + f(4) +f(5) = (0.10+0.05 +0.01 where Plx > 31 = Plx = 3| + Px= 41 + P[x 5] = (3) + (4) + f(5) = 0.10 + 0.05 +0.01 =0.16 Therefore, the probability that the majority of the stocks will increase in value is 0.16 (or 16%). 2. A coach has 6 players that will join track and field. The random vanable that is being studied is X, the number of players that will win. The probability function for this variable is shown in the table below. 1 3. 4. 0.05 0.02 )= P[X=x] 0.40 0.24 0.19 0.1 Question: Find the probability that the majority of the players will win the play? Solution and answer: 3. A census was conducted at a prison. All prisoners were asked how many tattoos they had which will serve as random vanable X. The table below shows the probability distribution for random variable X. 3 4 'DUCATION
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