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2. (а, By completing the square, show that 1/2 d.x x2 – x +1 3/3 By factoring x³+1 as a sum of cubes, rewrite the integral (Ь, in part (a). Then express 1/(x³ + 1) as the sum of a power series and use it to prove the following formula for T: 3/3 (-1)" 2 1 TT = 4 n=0 8n Зп + 1 Зп + 2

2. (а, By completing the square, show that 1/2 d.x x2 – x +1 3/3 By factoring x³+1 as a sum of cubes, rewrite the integral (Ь, in part (a). Then express 1/(x³ + 1) as the sum of a power series and use it to prove the following formula for T: 3/3 (-1)" 2 1 TT = 4 n=0 8n Зп + 1 Зп + 2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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can you help me on (b) ?thanks

2. (a) By completing the square, show that •1/2 dx x2 – x + 1 3/3 (b) in part (a). Then express 1/(x³ + 1) as the sum of a power series and use it to prove the following formula for T: By factoring x³ +1 as a sum of cubes, rewrite the integral 3/3 (-1)" 2 1 8n Зп + 1 Зп + 2 n=0
Transcribed Image Text:2. (a) By completing the square, show that •1/2 dx x2 – x + 1 3/3 (b) in part (a). Then express 1/(x³ + 1) as the sum of a power series and use it to prove the following formula for T: By factoring x³ +1 as a sum of cubes, rewrite the integral 3/3 (-1)" 2 1 8n Зп + 1 Зп + 2 n=0
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