2. A binary mixture of ethanol(1)/1-propanol(2) in a vessel at T = 86.85°C exists as saturated vapor and saturated liquid at equilibrium, with the vapor phase comprising 50.4% of the system. The composition of the vapor phase is Y₁ = 0.317. Assuming Raoult's law is valid: a. What is the pressure P in the vessel? b. At least how much should the P in the vessel be, at the same T, for the entire binary mixture to be in the liquid phase? ethanol(1): 1-propanol(2): B T/°C + C B = 3795.17 B = 3483.67 In Psat/kPa = A -- A = 16.8958 A = 16.1154 C = 230.918 C = 205.807
2. A binary mixture of ethanol(1)/1-propanol(2) in a vessel at T = 86.85°C exists as saturated vapor and saturated liquid at equilibrium, with the vapor phase comprising 50.4% of the system. The composition of the vapor phase is Y₁ = 0.317. Assuming Raoult's law is valid: a. What is the pressure P in the vessel? b. At least how much should the P in the vessel be, at the same T, for the entire binary mixture to be in the liquid phase? ethanol(1): 1-propanol(2): B T/°C + C B = 3795.17 B = 3483.67 In Psat/kPa = A -- A = 16.8958 A = 16.1154 C = 230.918 C = 205.807
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:2. A binary mixture of ethanol(1)/1-propanol(2) in a vessel at T = 86.85°C
exists as saturated vapor and saturated liquid at equilibrium, with the vapor
phase comprising 50.4% of the system. The composition of the vapor phase is
y1 = 0.317. Assuming Raoult's law is valid:
a. What is the pressure P in the vessel?
b. At least how much should the P in the vessel be, at the same T, for the
entire binary mixture to be in the liquid phase?
B
In psat /kPa = A --
A = 16.8958
A = 16.1154
T/°C +C
B = 3795.17
B = 3483.67
C = 230.918
ethanol(1):
1-propanol(2):
C = 205.807
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