2. A beam of light with frequency f =600 THz (600 × 101²HZ) passesthrough a glass prism as shown inFigure 2. The prism is immersed inwater. The index of refraction ofwater is n = 1.3 and the index ofrefraction of the glass is n2 = 1.6. Thebeam is initially parallel to the base ofthe prism. The triangle shown is anequilateral triangle so that = 60 °.Calculate the four angles 0,,02, 03, andO4. Show your work.n1n2n1Figure 2

Given: Frequency, ν=600THz=600×1012HzRefractive index of water, n1=1.3Refractive index of glass, n2=1.6Angle, Φ=600 When light or other waves flow through a border between two distinct isotropic media, such as water, glass, or air, Snell's law is a formula used to describe the connection between the angles of incidence and refraction. Snell's law is a connection between the route traveled by a beam of light as it crosses the boundary or separation surface between two interacting substances and their respective refractive indices. The expression of Snell's law is: n1sinθ1=n2sinθ2 .... (1) As the beam is initially parallel to the base, using the adjacent side, Φ+θ1=900θ1=900-Φθ1=900-600θ1=300Use Snell's law to calculate θ2: n1sinθ1=n2sinθ2sinθ2=n1sinθ1n2θ2=sin-1n1sinθ1n2 .... (2) Substitute the value in equation (2). θ2=sin-11.3sin3001.6θ2=sin-11.30.51.6θ2=sin-10.651.6θ2=sin-10.40625θ2=23.970 Using the prism's property, θ2+θ3=Φθ3=Φ-θ2 .... (3) Substitute the value in equation (3). θ3=600-23.970θ3=36.030 Use Snell's law to calculate θ4: n2sinθ3=n1sinθ4sinθ4=n2sinθ3n1θ4=sin-1n2sinθ3n1 .... (4) Substitute the value in equation (2). θ4=sin-11.6sin36.0301.3θ4=sin-11.60.588281.3θ4=sin-10.941251.3θ4=46.390

Answered: 2. A beam of light with frequency f =…