2. A baseball is thrown vertically up with speed vo and is subject to a quadratic drag with magnitude f(v) = cu2. Choose coordinates with +y upward and write down the equation of motion for the upward journey. Solve the equation of motion by separating variables and express v(t) as a function of time. Note: dx S: 1 tan -1 a a To determine the maximum height ymax, a trick can be used (b) dv dy dv v = dt dv dy dt dy dv in the equation of motion and use separation of variables. Inte- dy Replace by 99 grating both sides gives y in terms of v. Show that ter+ 2 ter n Ymax 11 2 Vter 2g Vmg/c is the terminal speed. Note: where vter xdx 1 In(a2+2) a2 2 2

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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2. A baseball is thrown vertically up with speed vo and is subject to a quadratic drag with
magnitude f(v) = cu2.
Choose coordinates with +y upward and write down the equation of
motion for the upward journey. Solve the equation of motion by separating variables
and express v(t)
as a function of time. Note:
dx
S:
1
tan
-1
a
a
Transcribed Image Text:2. A baseball is thrown vertically up with speed vo and is subject to a quadratic drag with magnitude f(v) = cu2. Choose coordinates with +y upward and write down the equation of motion for the upward journey. Solve the equation of motion by separating variables and express v(t) as a function of time. Note: dx S: 1 tan -1 a a
To determine the maximum height ymax, a trick can be used
(b)
dv dy
dv
v =
dt
dv
dy dt
dy
dv
in the equation of motion and use separation of variables. Inte-
dy
Replace by
99
grating both sides gives y in terms of v. Show that
ter+
2
ter n
Ymax
11
2
Vter
2g
Vmg/c is the terminal speed. Note:
where vter
xdx
1
In(a2+2)
a2 2
2
Transcribed Image Text:To determine the maximum height ymax, a trick can be used (b) dv dy dv v = dt dv dy dt dy dv in the equation of motion and use separation of variables. Inte- dy Replace by 99 grating both sides gives y in terms of v. Show that ter+ 2 ter n Ymax 11 2 Vter 2g Vmg/c is the terminal speed. Note: where vter xdx 1 In(a2+2) a2 2 2
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