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2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of 0.22 A field current of 10 A produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open- circuit. Calculate the full-load regulation at p.f. 0.8 lag. [34.4%) og Rombay Unir 1978R)

2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of 0.22 A field current of 10 A produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open- circuit. Calculate the full-load regulation at p.f. 0.8 lag. [34.4%) og Rombay Unir 1978R)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of0.20. A field current of 10 A produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open- circuit. Calculate the full-load regulation at p.f. 0.8 lag. [34.4%) (Flectrical Technology, Bombay Univ. 1978)
Transcribed Image Text:2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of0.20. A field current of 10 A produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open- circuit. Calculate the full-load regulation at p.f. 0.8 lag. [34.4%) (Flectrical Technology, Bombay Univ. 1978)
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