2. A 23.0 cm diameter coil consists of 23 turns of cylindrical copper wire 2.60 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.50 x 10-3 T/s. Determine the current in the loop in milli- amps (the resistivity for copper is 1.72 x 10-22.m). mA

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**Problem 2: Electromagnetic Induction in a Coil**

A coil with a diameter of 23.0 cm consists of 23 turns of cylindrical copper wire, each 2.60 mm in diameter. The coil is exposed to a uniform magnetic field that is perpendicular to the plane of the coil and changes at a rate of 9.50 x 10⁻³ T/s. Determine the current flowing through the loop, in milliamps. The resistivity of copper is given as 1.72 x 10⁻⁸ Ω·m.

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Unit: mA

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This setup allows students to calculate the current generated in a loop due to a changing magnetic field, applying Faraday's law of electromagnetic induction and considering the resistivity properties of copper.
Transcribed Image Text:**Problem 2: Electromagnetic Induction in a Coil** A coil with a diameter of 23.0 cm consists of 23 turns of cylindrical copper wire, each 2.60 mm in diameter. The coil is exposed to a uniform magnetic field that is perpendicular to the plane of the coil and changes at a rate of 9.50 x 10⁻³ T/s. Determine the current flowing through the loop, in milliamps. The resistivity of copper is given as 1.72 x 10⁻⁸ Ω·m. [Insert input box here] Unit: mA --- This setup allows students to calculate the current generated in a loop due to a changing magnetic field, applying Faraday's law of electromagnetic induction and considering the resistivity properties of copper.
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