2. A 12V battery makes 1.5A of current througha 40, 30, and a 10 resistor.a. How much power does the battery supply?1.5AAV=12VV=OV2b. How much power is dissipated by the 40 resistor?bes in ad3Ωwwwwww1Ω-V=?4Ω1.5AWaral2c. If the potential at the negative end of the battery is OV, what is the potential V at thestar?

The power supply through the battery is given by P=VI=I2R where V is the voltage of the…

2. A 12V battery makes 1.5A of current through a 40, 30, and a 102 resistor. a. How much power does the battery supply? 1.5A AV=12V 2b. How much power is dissipated by the 402 resistor? V=OV 3Ω www 102 V=? S 402 1.5A 2c. If the potential at the negative end of the battery is OV, what is the potential V at the star?

2. A 12V battery makes 1.5A of current through a 40, 30, and a 102 resistor. a. How much power does the battery supply? 1.5A AV=12V 2b. How much power is dissipated by the 402 resistor? V=OV 3Ω www 102 V=? S 402 1.5A 2c. If the potential at the negative end of the battery is OV, what is the potential V at the star?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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