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2. A 0.50 Kg Cu container holds 1.00 kg of water at 20° C. A 0.10 kg iron ball at 120° C is dropped into the water. What is the final equilibrium temperature of the mixture? C of copper = 0.093 cal/ g C°; c of iron = 0.115 cal/g C° C ofwater = 1 cal/ g Co %3D

2. A 0.50 Kg Cu container holds 1.00 kg of water at 20° C. A 0.10 kg iron ball at 120° C is dropped into the water. What is the final equilibrium temperature of the mixture? C of copper = 0.093 cal/ g C°; c of iron = 0.115 cal/g C° C ofwater = 1 cal/ g Co %3D

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A 0.50 Kg Cu container holds 1.00 kg of water at 20 0 C. A 0.10 kg iron ball at
120 0 C is dropped into the water. What is the final equilibrium temperature
of the mixture? C of copper = 0.093 cal/ g C 0 ; c of iron = 0.115 cal/g C o
C ofwater = 1 cal/ g C o

2. A 0.50 Kg Cu container holds 1.00 kg of water at 20° C. A 0.10 kg iron ball at 120° C is dropped into the water. What is the final equilibrium temperature of the mixture? C of copper = 0.093 cal/ g C°; c of iron = 0.115 cal/g C° C ofwater = 1 cal/ g Co %3D
Transcribed Image Text:2. A 0.50 Kg Cu container holds 1.00 kg of water at 20° C. A 0.10 kg iron ball at 120° C is dropped into the water. What is the final equilibrium temperature of the mixture? C of copper = 0.093 cal/ g C°; c of iron = 0.115 cal/g C° C ofwater = 1 cal/ g Co %3D
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