2). 8(x) = Now A is it is given function real numbers. Therefore it is at 4 = -1 x = 2. lim f(x) = f(-¹1) 4+1+ 41-(-1)- 217 lim f (x) lim f(x) - 4x 거스1 an+b ;-/<< 2 -5x 122 and 7 lim f(x) 112- X(→ (-1) lim f(x) = lim (ax+b) ((--(-1)+ X(-+(-1)+ -4 Ao function is lim f(x) 1-2- using 20 lim 4x = lim f(x) = 1+2+ f(+2) = f(-1) Now By using defination of - - a+b = - 4 = -4 Continuous = 2a+b = -10 Jel we lim (-5x) = X+2+ -5/2) = Continuous - a+b at x=2 lim f(x) = f (2) 21+2+ lim (0x + b) = 20+b *+27 -10 Continuity a-b= 4 - 0 -10 Continuous m 120 (2) 20+ b = -10 20- -26= 8 + 36= ~18 = b = -6 (multiply by E =) 1a = -2] (Put value of to in em (10) b

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Functions
Section8.1: Concept Of A Function
Problem 100PS
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

2). f(x) =
Now
M-(-1)
A
it
is
is given function
real numbers. Therefore it
at
4 = -1
X = 2.
24-1-
lim f (x)
lim f(x) =
X(--(-1)+
lim f(x)
47
-5x
7 lim f(x)
2427
ax+b;-1<4 <2
22
and
-
using 1 20
As function is
lim f(x)
1-2-
2(→ (-1)
lim 4x =
-
43-1
lim (ax+b)
X(+(-1)+
U
-4
lim, f(x) = f(-1)
dovod
continuous
- 4
f(-1)
Now By using defination of continuity
- a+b = - 4
a-b= 4 - 0
=
2a+b= -10
се дел
Continuous
lim f(x) = lim (-5x) =
1+2+
X+2+
f(+2) =
-5/2)=
دا
at x=2
lim f(x) = f (2)
3+2+
- a+b
lim (0x+b) = 20+b
x+2
-10
-10
Continuous
€
24+b= -10
- 2b = 8
m
20-7²
+
3b = 18 ⇒b= -6
=) [a= -2] (Put value of bo in ein (1)
C
(multiply by in
Transcribed Image Text:2). f(x) = Now M-(-1) A it is is given function real numbers. Therefore it at 4 = -1 X = 2. 24-1- lim f (x) lim f(x) = X(--(-1)+ lim f(x) 47 -5x 7 lim f(x) 2427 ax+b;-1<4 <2 22 and - using 1 20 As function is lim f(x) 1-2- 2(→ (-1) lim 4x = - 43-1 lim (ax+b) X(+(-1)+ U -4 lim, f(x) = f(-1) dovod continuous - 4 f(-1) Now By using defination of continuity - a+b = - 4 a-b= 4 - 0 = 2a+b= -10 се дел Continuous lim f(x) = lim (-5x) = 1+2+ X+2+ f(+2) = -5/2)= دا at x=2 lim f(x) = f (2) 3+2+ - a+b lim (0x+b) = 20+b x+2 -10 -10 Continuous € 24+b= -10 - 2b = 8 m 20-7² + 3b = 18 ⇒b= -6 =) [a= -2] (Put value of bo in ein (1) C (multiply by in
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