メ=2 Зх-2 x+4 3. 5.

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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### Transcription for Educational Website:

---

**Question 5:**

A triangle is depicted with one side labeled \( 3x - 2 \) and the other side labeled \( x + 4 \). At the bottom, it is indicated that \( x = 3 \).

**Given:**
- One side of the triangle: \( 3x - 2 \)
- Other side of the triangle: \( x + 4 \)
- \( x = 3 \)

**Finding the lengths of the sides:**

1. Substitute \( x = 3 \) into \( 3x - 2 \):
   \[
   3(3) - 2 = 9 - 2 = 7
   \]
   Therefore, one side of the triangle is 7 units.

2. Substitute \( x = 3 \) into \( x + 4 \):
   \[
   3 + 4 = 7
   \]
   Therefore, the other side of the triangle is also 7 units.

**Conclusion:**
Both sides of the triangle are 7 units long.

---

**Question 6:**

A triangle labeled \( \triangle GKP \) is depicted with two right angles indicated inside smaller internal triangles. The lengths of the sides involved in the expressions are \( 5x - 8 \) and \( 2x + 13 \). 

**Details:**
- \( GK = 5x - 8 \)
- \( GP = 2x + 13 \)

**Since this is a geometric problem involving right angles, further steps would involve solving for \( x \) based on given conditions, which are not fully clear from the diagram provided.**

---

**Question 7:**

A linear diagram is drawn where \( A \), \( B \), and \( C \) are collinear points with \( D \) above \( B \) indicating a perpendicular bisector forming right angles with segments \( AB \) and \( BC \):

- \( AB = 6x \)
- \( BC = 9x - 27 \)
- \( BD \) is perpendicular to \( AC \)

The figure suggests the use of algebraic expressions to find lengths of segments.

**Given:**
- \( AB = 6x \)
- \( BC = 9x - 27 \)

If any values are provided or found for \( x \), lengths
Transcribed Image Text:### Transcription for Educational Website: --- **Question 5:** A triangle is depicted with one side labeled \( 3x - 2 \) and the other side labeled \( x + 4 \). At the bottom, it is indicated that \( x = 3 \). **Given:** - One side of the triangle: \( 3x - 2 \) - Other side of the triangle: \( x + 4 \) - \( x = 3 \) **Finding the lengths of the sides:** 1. Substitute \( x = 3 \) into \( 3x - 2 \): \[ 3(3) - 2 = 9 - 2 = 7 \] Therefore, one side of the triangle is 7 units. 2. Substitute \( x = 3 \) into \( x + 4 \): \[ 3 + 4 = 7 \] Therefore, the other side of the triangle is also 7 units. **Conclusion:** Both sides of the triangle are 7 units long. --- **Question 6:** A triangle labeled \( \triangle GKP \) is depicted with two right angles indicated inside smaller internal triangles. The lengths of the sides involved in the expressions are \( 5x - 8 \) and \( 2x + 13 \). **Details:** - \( GK = 5x - 8 \) - \( GP = 2x + 13 \) **Since this is a geometric problem involving right angles, further steps would involve solving for \( x \) based on given conditions, which are not fully clear from the diagram provided.** --- **Question 7:** A linear diagram is drawn where \( A \), \( B \), and \( C \) are collinear points with \( D \) above \( B \) indicating a perpendicular bisector forming right angles with segments \( AB \) and \( BC \): - \( AB = 6x \) - \( BC = 9x - 27 \) - \( BD \) is perpendicular to \( AC \) The figure suggests the use of algebraic expressions to find lengths of segments. **Given:** - \( AB = 6x \) - \( BC = 9x - 27 \) If any values are provided or found for \( x \), lengths
**Finding the Value of \(n\) in the Midsegment of a Triangle**

In problems 8 and 9, \(\overline{DE}\) is a midsegment of \(\triangle ABC\). We need to find the value of \(n\).

### Problem 8
In the diagram for problem 8:

- \(\triangle ABC\) is given with vertices \(A\), \(B\), and \(C\).
- \(\overline{DE}\) is a midsegment of \(\triangle ABC\), meaning \(\overline{DE}\) is parallel to \(\overline{AC}\) and half its length.
- \(DE\) is labeled with a length of 36.
- The length of \(AC\) is labeled as \(12n\).

**Diagrams Explanation:**

An incomplete triangle is shown with the midsegment \(\overline{DE}\) parallel to \(\overline{AC}\):
- \(A\) and \(B\) are positioned at the base, while \(C\) is the top vertex.
- \(DE\) (midsegment) is shorter, parallel, and situated between \(AB\) and \(AC\).
- \(DE = 36\)
- \(AC = 12n\)

### Problem 9
In the diagram for problem 9:

- \(\triangle ABC\) shows vertices \(A\), \(B\), and \(C\).
- \(\overline{DE}\) is a midsegment of \(\triangle ABC\), meaning \(\overline{DE}\) is parallel to \(\overline{BC}\) and half its length.
- \(DE\) is given as \(n + 7\).
- \(BC\) is given as \(3n + 12\).

**Diagram Explanation:**

An incomplete triangle is shown with the midsegment \(\overline{DE}\) parallel to \(\overline{BC}\):
- \(A\) and \(B\) are positioned at the left and bottom, while \(C\) is the right vertex.
- \(DE\) (midsegment) is shorter, parallel, and situated between \(AB\) and \(BC\).
- \(DE = n + 7\)
- \(BC = 3n + 12\)

**Solution Steps:**
1. For Problem 8:
Transcribed Image Text:**Finding the Value of \(n\) in the Midsegment of a Triangle** In problems 8 and 9, \(\overline{DE}\) is a midsegment of \(\triangle ABC\). We need to find the value of \(n\). ### Problem 8 In the diagram for problem 8: - \(\triangle ABC\) is given with vertices \(A\), \(B\), and \(C\). - \(\overline{DE}\) is a midsegment of \(\triangle ABC\), meaning \(\overline{DE}\) is parallel to \(\overline{AC}\) and half its length. - \(DE\) is labeled with a length of 36. - The length of \(AC\) is labeled as \(12n\). **Diagrams Explanation:** An incomplete triangle is shown with the midsegment \(\overline{DE}\) parallel to \(\overline{AC}\): - \(A\) and \(B\) are positioned at the base, while \(C\) is the top vertex. - \(DE\) (midsegment) is shorter, parallel, and situated between \(AB\) and \(AC\). - \(DE = 36\) - \(AC = 12n\) ### Problem 9 In the diagram for problem 9: - \(\triangle ABC\) shows vertices \(A\), \(B\), and \(C\). - \(\overline{DE}\) is a midsegment of \(\triangle ABC\), meaning \(\overline{DE}\) is parallel to \(\overline{BC}\) and half its length. - \(DE\) is given as \(n + 7\). - \(BC\) is given as \(3n + 12\). **Diagram Explanation:** An incomplete triangle is shown with the midsegment \(\overline{DE}\) parallel to \(\overline{BC}\): - \(A\) and \(B\) are positioned at the left and bottom, while \(C\) is the right vertex. - \(DE\) (midsegment) is shorter, parallel, and situated between \(AB\) and \(BC\). - \(DE = n + 7\) - \(BC = 3n + 12\) **Solution Steps:** 1. For Problem 8:
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