2 y=f(x) -5 2 (a) Find the domain of the function 1 g(x) = V1- f(x)" Explain your reasoning using complete sentences. Be sure to follow the ap- propriate template. (b) Sketch an accurate graph of the function h(x) = f(\x|). Explain your reasoning completely, using complete sentences. Label the co- ordinates of at least 5 critical points on the graph. %24

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem 1
**Use the graph of \( y = f(x) \) shown below to answer the following questions.**

[Insert Graph Image Description Here: The graph of \( y = f(x) \) is plotted on a coordinate plane. The x-axis ranges from -5 to 5, and the y-axis ranges from -4 to 4. The graph appears to be a smooth, continuous curve with a mixture of concave upward and downward sections, having multiple critical points where the slope changes.]

**(a) Find the domain of the function**

\[ g(x) = \frac{1}{\sqrt{1 - f(x)}}. \]

Explain your reasoning using complete sentences. Be sure to follow the appropriate template.

**(b) Sketch an accurate graph of the function**

\[ h(x) = f(|x|). \]

Explain your reasoning completely, using complete sentences. Label the coordinates of at least 5 critical points on the graph.

---

### Detailed Graph Description
- **Axes and Scale:**
  - The x-axis goes from -5 to 5.
  - The y-axis goes from -4 to 4.
  
- **Graph of \( y = f(x) \):**
  - The graph is a continuous curve.
  - The curve starts from above the y-axis at an upward slope, then decreases, crosses the y-axis and dips down to a minimum point before rising again, crossing the x-axis, reaching a local maximum, and descending again.
  - Key points on the graph include:
    - A local minimum around \( (0, -4.4) \).
    - A local maximum around \( (2.5, 2.3) \).
    - Other key intercepts at the x-axis around \( (1, 0) \), \( (-2.7, 0) \), and at the y-axis \( (0,0) \).

### Questions Breakdown

**(a) Find the domain of the function**

\[ g(x) = \frac{1}{\sqrt{1 - f(x)}}. \]

*Explanation:*

First, we need to determine for which values of \( x \), \( 1 - f(x) \) is positive since the expression inside the square root must be greater than 0 to be defined.

- Find where \( f(x) < 1 \) since \( 1 - f(x) >
Transcribed Image Text:### Problem 1 **Use the graph of \( y = f(x) \) shown below to answer the following questions.** [Insert Graph Image Description Here: The graph of \( y = f(x) \) is plotted on a coordinate plane. The x-axis ranges from -5 to 5, and the y-axis ranges from -4 to 4. The graph appears to be a smooth, continuous curve with a mixture of concave upward and downward sections, having multiple critical points where the slope changes.] **(a) Find the domain of the function** \[ g(x) = \frac{1}{\sqrt{1 - f(x)}}. \] Explain your reasoning using complete sentences. Be sure to follow the appropriate template. **(b) Sketch an accurate graph of the function** \[ h(x) = f(|x|). \] Explain your reasoning completely, using complete sentences. Label the coordinates of at least 5 critical points on the graph. --- ### Detailed Graph Description - **Axes and Scale:** - The x-axis goes from -5 to 5. - The y-axis goes from -4 to 4. - **Graph of \( y = f(x) \):** - The graph is a continuous curve. - The curve starts from above the y-axis at an upward slope, then decreases, crosses the y-axis and dips down to a minimum point before rising again, crossing the x-axis, reaching a local maximum, and descending again. - Key points on the graph include: - A local minimum around \( (0, -4.4) \). - A local maximum around \( (2.5, 2.3) \). - Other key intercepts at the x-axis around \( (1, 0) \), \( (-2.7, 0) \), and at the y-axis \( (0,0) \). ### Questions Breakdown **(a) Find the domain of the function** \[ g(x) = \frac{1}{\sqrt{1 - f(x)}}. \] *Explanation:* First, we need to determine for which values of \( x \), \( 1 - f(x) \) is positive since the expression inside the square root must be greater than 0 to be defined. - Find where \( f(x) < 1 \) since \( 1 - f(x) >
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