(-2)" (x+2)". n=1

Q: x-6/2=5-x+2/3

A: Given expression is,

Q: 3(x + 5) = 18

A:

Q: |3x − 4| = 8

A: Given that |3x − 4| = 8

Q: -10(x-7)– 7(x+ 2)

A: i -10x-7-7x+2=-10x-10-7-7x-72=-10x+70-7x-14=-17x+56

Q: 256 = (1/4) 3x +2

A: We have to solve the given equation. Using am=1/a-m and (ab)m=ambm

Q: 6 Q3. Evaluate Σή=1 5n2 - 7n.

A:

Q: (x+8)2=7

A: Given: (x+8)2=7

Q: -1/2(6p+16)=7

A: -1/2(6p+16)=7

Q: 6 = -4(1 - x) + 3(x + 1)

A: Given:

Q: (-x - 3) + (3x + 8)

A: Here we have to solve the given expression.

Q: (-1)^-1 00 16. n=1 vn+10

A:

Q: 0.5 (x + 7) + 9 = 43

A: Given 0.5 (x + 7) + 9 = 43

Q: -2(x-4)+12(3-2x)=-8

A:

Q: 5/4(x+8)+1/4x=-9

A: here we have to solve ,  -54(x+8)+14x=-9

Q: simplify (5/6 g- 7/8 h) + (4/9g+7/12h-5)

A: Given, 56g- 78h + 49g+712h-5

Q: Write each expression in the form 2 or 3 for a suitable constant k. 2x () - 3x 1 (b) 81 x/2 (a) 8…

A: We will use algebraic property of power And write that in 2^(kx) or 3^(kx) form

Q: [50-(4+8)+3]-[30+(18-3)]-

A:

Q: |8x - 7|-1= 10

A:

Q: E=D{(r,0,2): 0s es n, Os zs 1, Vzs rs 1.

A: Given,          E=r, θ, z : 0≤θ≤π, 0≤z≤1, z≤r≤1 To find:           ∫∫∫Ey2ex2+y23dV

Q: x-2.5)⁴ + ( x- 1.5)⁴ = 1 in Real Numbers

A:

Q: 5(22x+1) = 8x

A:

Q: 6(x+9)=2

A:

Q: For each of the following sequences, if the divergence test applies, either state that lim an does…

A:

Q: x + 4y = –8 x – 4y = –8

A: The given system of linear equations is consistent and has unique solution.

Q: Hi.  I need help.   (1/x-2)+(3/x+3)=4/x2+x-6

A: We have to prove both the sides

Q: The product of 2 and 8 is more than 8? T/F

A:

Q: (-4)* 5k +1 k=1

A: We have to find if the series convergent or divergent.

Q: (a + 5) = 49 x +5 2.

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.