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2 (x-y) (1- y') = 1 +y', 2 (x-y) - 2 (x-y) y' = 1 +y' ,

2 (x-y) (1- y') = 1 +y', 2 (x-y) - 2 (x-y) y' = 1 +y' ,

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hey! Can you explain why the top equation is equal to the bottom one. i am in the middle of som implict diffrentiation

2 (x-y) (1- y') = 1 +y', 2 (x-y) - 2 (x-y) y' = 1 + y' ,
Transcribed Image Text:2 (x-y) (1- y') = 1 +y', 2 (x-y) - 2 (x-y) y' = 1 + y' ,
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Explanation of the solution is given below....and in the top equation we multiplying to each other and then we get the form of bottom equation.

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