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2 + x 3 = The rational equation x+2 is solved for x using the work shown below. X x(2 + x) = 3(x + 2) x² + 2x = 3x + 6 x²-x-6=0 (x - 3)(x + 2) = 0 x = 3 or x = -2 Which statement correctly completes the solution. Select one: O a. Both x = 3 and x = -2 are extraneous solutions. O b. The solution x = 3 is a valid solution, but x = -2 is an extraneous solution. Both x = 3 and x = -2 are valid solutions. O c. Od. The solution x = -2 is a valid solution, but x = 3 is an extraneous solution.

2 + x 3 = The rational equation x+2 is solved for x using the work shown below. X x(2 + x) = 3(x + 2) x² + 2x = 3x + 6 x²-x-6=0 (x - 3)(x + 2) = 0 x = 3 or x = -2 Which statement correctly completes the solution. Select one: O a. Both x = 3 and x = -2 are extraneous solutions. O b. The solution x = 3 is a valid solution, but x = -2 is an extraneous solution. Both x = 3 and x = -2 are valid solutions. O c. Od. The solution x = -2 is a valid solution, but x = 3 is an extraneous solution.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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3 2+3 The rational equation is solved for x using the work shown below. x(2 + x) = 3(x + 2) x² + 2x = 3x + 6 x²-x-6=0 (x - 3)(x + 2) = 0 x = 3 or x = -2 Which statement correctly completes the solution. Select one: O a. Both x = 3 and x = -2 are extraneous solutions. O b. The solution x = 3 is a valid solution, but x = -2 is an extraneous solution. Both x = 3 and x = -2 are valid solutions. O c. O d. The solution x = -2 is a valid solution, but x = 3 is an extraneous solution. II
Transcribed Image Text:3 2+3 The rational equation is solved for x using the work shown below. x(2 + x) = 3(x + 2) x² + 2x = 3x + 6 x²-x-6=0 (x - 3)(x + 2) = 0 x = 3 or x = -2 Which statement correctly completes the solution. Select one: O a. Both x = 3 and x = -2 are extraneous solutions. O b. The solution x = 3 is a valid solution, but x = -2 is an extraneous solution. Both x = 3 and x = -2 are valid solutions. O c. O d. The solution x = -2 is a valid solution, but x = 3 is an extraneous solution. II
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