2) X 144 + (y - 5) - 16 = 1 ||

Q: 13) 2 X 121 + (y − 1)² = 1

A:

Q: (x + 1)² (y-8)² (v-8)² = 1 - + 9 81

A: Given query is to find the conic form.

Q: 15. x2 - 8x + 2y + 10 = 0

A:

Q: 9y^2-16x^2=81 Find the coordinates of the vertices and foci of the hyperbola equation.

A: Solution of question is written in below steps.

Q: 10) (x + 7)²_ (y + 4)² = 1 + 81 36

A:

Q: What are the coordinates of the vertex for the given equation in standard form? y=x^2+6x+5

A:

Q: 66. One parabola at the right has the equation y-&-4)+ 2. Which equation represents the second…

A: Solution is given as below:

Q: Write an equation for each hyperbola. : 45. vertices at (0, 6), (0, -6); asymptotes y = ± ½ x

A: Given: 1. Vertices of hyperbola are at (0,6) and (0,-6).  (Which indicate that given hyperbola is…

Q: 4) x² (1-8)² + 100 25 =1

A:

Q: Determine the vertex of a parabola y=-2x^2+15x using calculus (use first principles to solve)

A:

Q: Write an equation of the ellipse in standard form ((x-h)/a)^2 + ((y-k)/b)^2 =1

A: Standard form of ellipse isx-h2a2+y-k2b2=1

Q: Solve equation. Give the exact solution. Answer should be as a comma-separated list) 3x^2+3x = 1/9

A:

Q: 12) (x − 8)²(y+7)² - + 100 25 (x + 2)²_ (y − 1)² 4 64 YG X 14) = 1 G = 1

A:

Q: Write the equation of the hyperbola 25x^2-9y^2-150x-36y-36=0 in standard form.

A:

Q: Can you please solve 4x^2+3y^2+12y-36=0 this equation in the form of the standard ellipse equation?…

A: Here the given equation is,  4x2+3y2+12y-36=0 The standard form of the ellipse is  (x-h)2/a2 +…

Q: Which of the equations below also represents the parabola y=−3x^2−18x+16? (options in image)

A:

Q: 9) (x - 2)² 16 9 (x+5)² ¸ (v+3)² _ 1 = + 25 16 +(y-1)² = 1 11) 2 x² X 13) 121

A:

Q: Write the equation of the parabola x^2+10x+20y+45=0 in the standard form for parabolas

A:

Q: Write the equation of two different parabolas that have a vertex of (3,-1), and that pass through…

A: Vertex is ( 3 , -1 )  and point (0, 2 ) So Now equation of parabola is given by    y = a ( x - h )2…

Q: Determine the equation of a parabola

A: Substituting the point origin, in standard equation we get value of directrix. Then we can find…

Q: Find the general conic form. The final answer should look something like this x^2+4y^2-64y=-156

A: