2) Write a formula for an exponential function with an initial value of 700 that decreases at a fixed percentage rate of 6.4% per unit time. Provide a brief explanation of your thinking.
2) Write a formula for an exponential function with an initial value of 700 that decreases at a fixed percentage rate of 6.4% per unit time. Provide a brief explanation of your thinking.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**2) Exponential Function Problem:**
Write a formula for an exponential function with an initial value of 700 that decreases at a fixed percentage rate of 6.4% per unit time. Provide a brief explanation of your thinking.
**Solution:**
An exponential function that models decay can be written as:
\[ f(t) = a \cdot (1 - r)^t \]
where:
- \( a \) is the initial value,
- \( r \) is the rate of decay (as a decimal),
- \( t \) is the time.
For this problem:
- Initial value \( a = 700 \),
- Rate of decay \( r = 0.064 \).
Thus, the formula is:
\[ f(t) = 700 \cdot (1 - 0.064)^t = 700 \cdot 0.936^t \]
**3) Linear Function Problem:**
Suppose \( f(x) = \frac{2x + 7}{3} \). Determine the formula for a linear function that is perpendicular to \( f(x) \) and goes through the point (47, -115). Provide a brief explanation of your thinking.
**Solution:**
The slope (\( m \)) of a linear function \( f(x) = \frac{2}{3}x + \frac{7}{3} \).
To find a perpendicular line, use the negative reciprocal of the slope:
- Slope of the perpendicular line = \(-\frac{3}{2}\).
To find the equation of the line, use the point-slope form:
\[ y - y_1 = m(x - x_1) \]
Using the point \( (47, -115) \):
\[ y + 115 = -\frac{3}{2}(x - 47) \]
Simplifying:
\[ y = -\frac{3}{2}x + \frac{3}{2} \cdot 47 - 115 \]
\[ y = -\frac{3}{2}x + 70.5 - 115 \]
\[ y = -\frac{3}{2}x - 44.5 \]
Thus, the equation of the linear function is:
\[ y = -\frac{3}{2}x + 44.5 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92ab3c20-a3cd-4c1e-8775-52ac5ed4d4cf%2Ff4ba1a56-42e6-465c-8b22-f9c63edacc6a%2Fmc6p5x_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**2) Exponential Function Problem:**
Write a formula for an exponential function with an initial value of 700 that decreases at a fixed percentage rate of 6.4% per unit time. Provide a brief explanation of your thinking.
**Solution:**
An exponential function that models decay can be written as:
\[ f(t) = a \cdot (1 - r)^t \]
where:
- \( a \) is the initial value,
- \( r \) is the rate of decay (as a decimal),
- \( t \) is the time.
For this problem:
- Initial value \( a = 700 \),
- Rate of decay \( r = 0.064 \).
Thus, the formula is:
\[ f(t) = 700 \cdot (1 - 0.064)^t = 700 \cdot 0.936^t \]
**3) Linear Function Problem:**
Suppose \( f(x) = \frac{2x + 7}{3} \). Determine the formula for a linear function that is perpendicular to \( f(x) \) and goes through the point (47, -115). Provide a brief explanation of your thinking.
**Solution:**
The slope (\( m \)) of a linear function \( f(x) = \frac{2}{3}x + \frac{7}{3} \).
To find a perpendicular line, use the negative reciprocal of the slope:
- Slope of the perpendicular line = \(-\frac{3}{2}\).
To find the equation of the line, use the point-slope form:
\[ y - y_1 = m(x - x_1) \]
Using the point \( (47, -115) \):
\[ y + 115 = -\frac{3}{2}(x - 47) \]
Simplifying:
\[ y = -\frac{3}{2}x + \frac{3}{2} \cdot 47 - 115 \]
\[ y = -\frac{3}{2}x + 70.5 - 115 \]
\[ y = -\frac{3}{2}x - 44.5 \]
Thus, the equation of the linear function is:
\[ y = -\frac{3}{2}x + 44.5 \]
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