I'm confused about how to solve this. [2] Water in a U-tube is held at unequal heights by placing a thumb over one end. Thediameter of the tube is 1.5 cm and the total length of the water column is 8 cm, top rightto top left.The initial height difference is h as shown in the figure.(a) if we set y=0 at the equilibrium height for the water, what is thevalue of y, = y (t = 0) for the right column?(b) When the thumb is removed, what happens during the next severalseconds?(c) Set up Newton's 2nd law for the water column starting with the pressures.(d) Compare the result with the oscillator equation and determine the expression for theangular frequency .(e) Student I. Maslow Starter began the data collection 0.5[s] after the thumb wasremoved. The height y at that time was 0.8yo. Determine the velocity of the water columnat that time in terms of g. p & yo.(f) Use your values of yo & the initial velocity v, to determine the amplitudes A & B iny = Acos (at) + B sin(@t) and, from those, find the amplitude D and phase shift d iny = D cos( ot + 8)(9) The amplitude of the motion decreases by 10% per period. Determine the dampingconstant B in e, the damping coefficient, b in F = -by and the resonance frequency ofthe damped oscillator.

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[2] Water in a U-tube is held at unequal heights by placing a thumb over one end. The diameter of the tube is 1.5 cm and the total length of the water column is 8 cm, top right to top left. The initial height difference is h as shown in the figure. (a) if we set y=0 at the equilibrium height for the water, what is the value of y, = y (t=0) for the right column? (b) When the thumb is removed, what happens during the next several seconds? (c) Set up Newton's 2nd law for the water column starting with the pressures.

[2] Water in a U-tube is held at unequal heights by placing a thumb over one end. The diameter of the tube is 1.5 cm and the total length of the water column is 8 cm, top right to top left. The initial height difference is h as shown in the figure. (a) if we set y=0 at the equilibrium height for the water, what is the value of y, = y (t=0) for the right column? (b) When the thumb is removed, what happens during the next several seconds? (c) Set up Newton's 2nd law for the water column starting with the pressures.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

I'm confused about how to solve this.

[2] Water in a U-tube is held at unequal heights by placing a thumb over one end. The
diameter of the tube is 1.5 cm and the total length of the water column is 8 cm, top right
to top left.
The initial height difference is h as shown in the figure.
(a) if we set y=0 at the equilibrium height for the water, what is the
value of y, = y (t = 0) for the right column?
(b) When the thumb is removed, what happens during the next several
seconds?
(c) Set up Newton's 2nd law for the water column starting with the pressures.
(d) Compare the result with the oscillator equation and determine the expression for the
angular frequency .
(e) Student I. Maslow Starter began the data collection 0.5[s] after the thumb was
removed. The height y at that time was 0.8yo. Determine the velocity of the water column
at that time in terms of g. p & yo.
(f) Use your values of yo & the initial velocity v, to determine the amplitudes A & B in
y = Acos (at) + B sin(@t) and, from those, find the amplitude D and phase shift d in
y = D cos( ot + 8)
(9) The amplitude of the motion decreases by 10% per period. Determine the damping
constant B in e, the damping coefficient, b in F = -by and the resonance frequency of
the damped oscillator.

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