2) Use the given data to find the minimum sample size required to estimate the population proportion. (a) Margin of error: 0.04, confidence level: 95%, p = 0.64 (b) Margin of error: 0.006, confidence level: 95%, § and ĝ are unknown

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### MATH110 Problem Set 04

#### Problem 2

Use the given data to find the minimum sample size required to estimate the population proportion.

(a) **Parameters:**
- Margin of Error: 0.04
- Confidence Level: 95%
- Estimated Proportion (\(\hat{p}\)): 0.64

(b) **Parameters:**
- Margin of Error: 0.006
- Confidence Level: 95%
- Estimated Proportion (\(\hat{p}\)) and Complement (\(\hat{q}\)) are unknown

#### Problem 3

Use the given degree of confidence and sample data to construct a confidence interval for the population mean \(\mu\). Assume that the population has a normal distribution.
Transcribed Image Text:### MATH110 Problem Set 04 #### Problem 2 Use the given data to find the minimum sample size required to estimate the population proportion. (a) **Parameters:** - Margin of Error: 0.04 - Confidence Level: 95% - Estimated Proportion (\(\hat{p}\)): 0.64 (b) **Parameters:** - Margin of Error: 0.006 - Confidence Level: 95% - Estimated Proportion (\(\hat{p}\)) and Complement (\(\hat{q}\)) are unknown #### Problem 3 Use the given degree of confidence and sample data to construct a confidence interval for the population mean \(\mu\). Assume that the population has a normal distribution.
**MATH110 Problem Set 04**

1) Construct a confidence interval for the population proportion \( p \).

- \( n = 144 \)
- \( x = 86 \)
- 90% confidence

**Explanation:**

This problem asks you to construct a confidence interval for the population proportion \( p \). Given:

- \( n = 144 \): the sample size.
- \( x = 86 \): the number of successes in the sample.
- A confidence level of 90%.

To solve this, you will calculate the sample proportion \( \hat{p} = \frac{x}{n} \) and use the standard error to construct the confidence interval. The formula for a confidence interval at a 90% confidence level is:

\[ \hat{p} \pm Z \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \]

where \( Z \) is the Z-score corresponding to the desired confidence level.
Transcribed Image Text:**MATH110 Problem Set 04** 1) Construct a confidence interval for the population proportion \( p \). - \( n = 144 \) - \( x = 86 \) - 90% confidence **Explanation:** This problem asks you to construct a confidence interval for the population proportion \( p \). Given: - \( n = 144 \): the sample size. - \( x = 86 \): the number of successes in the sample. - A confidence level of 90%. To solve this, you will calculate the sample proportion \( \hat{p} = \frac{x}{n} \) and use the standard error to construct the confidence interval. The formula for a confidence interval at a 90% confidence level is: \[ \hat{p} \pm Z \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \] where \( Z \) is the Z-score corresponding to the desired confidence level.
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