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2) This table has three columns. First, match each set of Boundary Conditions (the left column) to the 4 beams (center column). Then, get some scratch paper. For each of the 4 beams (center column), create a FBD that cuts at distance x from the origin. Use that scratch paper to match the 4 beams (center column) to the 4 FBDs (right column). You will draw a total of eight lines.

2) This table has three columns. First, match each set of Boundary Conditions (the left column) to the 4 beams (center column). Then, get some scratch paper. For each of the 4 beams (center column), create a FBD that cuts at distance x from the origin. Use that scratch paper to match the 4 beams (center column) to the 4 FBDs (right column). You will draw a total of eight lines.

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter12: Electric Current And Related Variables In Engineering
Section12.2: Electrical Circuits And Components
Problem 6BYG
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Question
(2) This table has three columns. First, match each set of Boundary Conditions (the left column) to the 4 beams (center column). Then, get some scratch paper. For each of the 4 beams (center column), create a FBD that cuts at distance x from the origin. Use that scratch paper to match the 4 beams (center column) to the 4 FBDs (right column). You will draw a total of eight lines. BEAMS: FBDs: BOUNDARY CONDITIONS: (2m)=0 V(2m)=0 0 (0)=0 V (0)=0 V(0)=0 V(2m)=0 √(-1m)=0 V(+1m)=0 ORIGIN ORIGIN ORIGIN Im- 2m 2m 2m ORIGIN x x x U +(-x)+
Transcribed Image Text:(2) This table has three columns. First, match each set of Boundary Conditions (the left column) to the 4 beams (center column). Then, get some scratch paper. For each of the 4 beams (center column), create a FBD that cuts at distance x from the origin. Use that scratch paper to match the 4 beams (center column) to the 4 FBDs (right column). You will draw a total of eight lines. BEAMS: FBDs: BOUNDARY CONDITIONS: (2m)=0 V(2m)=0 0 (0)=0 V (0)=0 V(0)=0 V(2m)=0 √(-1m)=0 V(+1m)=0 ORIGIN ORIGIN ORIGIN Im- 2m 2m 2m ORIGIN x x x U +(-x)+
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