[2] The switch 'Sw' closes at t=D0. Determine the expression for capacitor voltage vc(t) for t>0 secs. Indicate voltage polarity across the capacitor.. (12) .... R1 Sw Vs 10 2 R4 10 2 10 V R2 R6 C1 10 2 10 2 160 uF R5 Is 10 Ω 1 A R3 10 2

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### Determining the Capacitor Voltage Expression

#### Problem Statement:
The switch 'Sw' closes at t = 0. Determine the expression for capacitor voltage \( v_C(t) \) for \( t > 0 \) seconds. Indicate the voltage polarity across the capacitor.

---

#### Circuit Diagram:
The circuit diagram consists of the following components:

1. Voltage Source \( V_s \) (10 V)
2. Current Source \( I_s \) (1 A)
3. Resistors:
   - \( R_1 \) = 10 Ω
   - \( R_2 \) = 10 Ω
   - \( R_3 \) = 10 Ω
   - \( R_4 \) = 10 Ω
   - \( R_5 \) = 10 Ω
   - \( R_6 \) = 10 Ω
4. Capacitor \( C_1 \) = 160 μF
5. Switch \( Sw \)

The arrangement of the circuit is as follows:

- The voltage source \( V_s \) and current source \( I_s \) are connected in parallel.
- Resistor \( R_1 \) is connected to the positive end of the voltage source.
- The other end of \( R_1 \) connects to one terminal of \( R_4 \) and the switch \( Sw \).
- The other end of \( Sw \) connects to \( R_6 \) which is in series with the capacitor \( C_1 \).
- The negative terminal of \( C_1 \) is connected back to the parallel combination of \( R_2 \) and \( R_3 \).

---

#### Analysis to Determine \( v_C(t) \):

To determine the expression for the capacitor voltage \( v_C(t) \) for \( t > 0 \):

1. **Initial Condition Analysis:**
    - Before the switch is closed (at \( t < 0 \)), the capacitor \( C_1 \) might be uncharged or at a particular initial voltage depending on the initial conditions.
  
2. **At t = 0:**
    - When the switch \( Sw \) closes at \( t = 0 \), the circuit starts to charge the capacitor \( C_1 \). The voltage across the capacitor \( v_C \) will change over time as it charges or discharges.

3. **Time Domain Analysis:**
Transcribed Image Text:--- ### Determining the Capacitor Voltage Expression #### Problem Statement: The switch 'Sw' closes at t = 0. Determine the expression for capacitor voltage \( v_C(t) \) for \( t > 0 \) seconds. Indicate the voltage polarity across the capacitor. --- #### Circuit Diagram: The circuit diagram consists of the following components: 1. Voltage Source \( V_s \) (10 V) 2. Current Source \( I_s \) (1 A) 3. Resistors: - \( R_1 \) = 10 Ω - \( R_2 \) = 10 Ω - \( R_3 \) = 10 Ω - \( R_4 \) = 10 Ω - \( R_5 \) = 10 Ω - \( R_6 \) = 10 Ω 4. Capacitor \( C_1 \) = 160 μF 5. Switch \( Sw \) The arrangement of the circuit is as follows: - The voltage source \( V_s \) and current source \( I_s \) are connected in parallel. - Resistor \( R_1 \) is connected to the positive end of the voltage source. - The other end of \( R_1 \) connects to one terminal of \( R_4 \) and the switch \( Sw \). - The other end of \( Sw \) connects to \( R_6 \) which is in series with the capacitor \( C_1 \). - The negative terminal of \( C_1 \) is connected back to the parallel combination of \( R_2 \) and \( R_3 \). --- #### Analysis to Determine \( v_C(t) \): To determine the expression for the capacitor voltage \( v_C(t) \) for \( t > 0 \): 1. **Initial Condition Analysis:** - Before the switch is closed (at \( t < 0 \)), the capacitor \( C_1 \) might be uncharged or at a particular initial voltage depending on the initial conditions. 2. **At t = 0:** - When the switch \( Sw \) closes at \( t = 0 \), the circuit starts to charge the capacitor \( C_1 \). The voltage across the capacitor \( v_C \) will change over time as it charges or discharges. 3. **Time Domain Analysis:**
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