2) The line segment from (3,0, 1) to (1,4,-2) can be parameterized by: x 3 - 2t y = 4t - Z= 1-3t with t going from 0 to 1, or by х— х y = 6 2x 7 3 х 2 Z = 2 with x going from 3 to 1. Show that both parameterizations yield the same result when using the pullback to compute the integral of 6dx - 2dy + dz over the line segment from (3,0,1) to (1,4,-2)
2) The line segment from (3,0, 1) to (1,4,-2) can be parameterized by: x 3 - 2t y = 4t - Z= 1-3t with t going from 0 to 1, or by х— х y = 6 2x 7 3 х 2 Z = 2 with x going from 3 to 1. Show that both parameterizations yield the same result when using the pullback to compute the integral of 6dx - 2dy + dz over the line segment from (3,0,1) to (1,4,-2)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![2) The line segment from (3,0, 1) to (1,4,-2) can be parameterized by:
x 3 - 2t
y = 4t
-
Z= 1-3t
with t going from 0 to 1, or by
х— х
y = 6 2x
7
3
х
2
Z =
2
with x going from 3 to 1. Show that both parameterizations yield the same result when using
the pullback to compute the integral of 6dx - 2dy + dz over the line segment from (3,0,1)
to (1,4,-2)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0548f28d-2867-4ce8-91e2-809a65372be3%2Fc8bb077e-efd4-4506-9a5c-d7105ff2f897%2Fgzml4t.png&w=3840&q=75)
Transcribed Image Text:2) The line segment from (3,0, 1) to (1,4,-2) can be parameterized by:
x 3 - 2t
y = 4t
-
Z= 1-3t
with t going from 0 to 1, or by
х— х
y = 6 2x
7
3
х
2
Z =
2
with x going from 3 to 1. Show that both parameterizations yield the same result when using
the pullback to compute the integral of 6dx - 2dy + dz over the line segment from (3,0,1)
to (1,4,-2)
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