2 tana-2 tan b = 2 tan x -1 tan a- tan b = tan¬1 x %3D a-b - a-bten- 1+ab tan = tan a-b X =- 1+ ab हल कीजिए- tan (x+1)+ tan (x-1) = tan 17 नीकरण है-
2 tana-2 tan b = 2 tan x -1 tan a- tan b = tan¬1 x %3D a-b - a-bten- 1+ab tan = tan a-b X =- 1+ ab हल कीजिए- tan (x+1)+ tan (x-1) = tan 17 नीकरण है-
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question

Transcribed Image Text:गणित (छत्त
2 tan a-2 tanb = 2 tanx
-1
-1
tan a- tan b = tan¬
%3D
tan- a-6
= tan
1+ ab
a-b
1+ ab
रण हल कीजिए-
6.
tan (x+1)+ tan (x-1) = tan
17
समीकरण है-
6.
an(x+1)+tan(x-1) = tan
-1
%3D
17
6.
= tan
17
x+1+x-1
-1
tan
1-(x+1)(x-1)
2x
6
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