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√2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0 = 360°k, 225° + 360°k, 315° + 360°k 0 = 360°k, 45° + 360°k, 45° +180°k O 0 = 0° +180°k, 225° + 360°k, 315° + 360°k 0 = 0° +180°k, 45° + 360°k, 45° + 180°k 8 = 180° + 360°k, 225° + 360°k, 315° + 360°k (b) 0 if 0° ≤ 0 < 360° e = 0°, 225°, 315°, 405° x Read It Watch It Need Help? (Enter your answers as a comma-separated list.)

√2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0 = 360°k, 225° + 360°k, 315° + 360°k 0 = 360°k, 45° + 360°k, 45° +180°k O 0 = 0° +180°k, 225° + 360°k, 315° + 360°k 0 = 0° +180°k, 45° + 360°k, 45° + 180°k 8 = 180° + 360°k, 225° + 360°k, 315° + 360°k (b) 0 if 0° ≤ 0 < 360° e = 0°, 225°, 315°, 405° x Read It Watch It Need Help? (Enter your answers as a comma-separated list.)

Trigonometry (11th Edition)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Section 6.1 question 17
Solve for all degree solutions and 0 if 0° ≤ 0 < 360°. Do not use a calculator. (Enter your answers as a comma-separated list.) √2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0=360°k, 225° + 360°k, 315° + 360°k 0 = 360°k, 45° + 360°k, 45° + 180°k O = 0° +180°k, 225° + 360°k, 315° + 360°k 0 0 = 0° + 180°k, 45° + 360°k, 45° +180°k 0 = 180° + 360°k, 225° + 360°k, 315° + 360°k (b) 0 if 0° ≤ 0 < 360° e = 0°, 225°, 315°, 405° x Read It Watch It Need Help?
Transcribed Image Text:Solve for all degree solutions and 0 if 0° ≤ 0 < 360°. Do not use a calculator. (Enter your answers as a comma-separated list.) √2 tan 0 + 2 sin 0 tan 0 = 0 (a) all degree solutions (Let k be any integer.) 0=360°k, 225° + 360°k, 315° + 360°k 0 = 360°k, 45° + 360°k, 45° + 180°k O = 0° +180°k, 225° + 360°k, 315° + 360°k 0 0 = 0° + 180°k, 45° + 360°k, 45° +180°k 0 = 180° + 360°k, 225° + 360°k, 315° + 360°k (b) 0 if 0° ≤ 0 < 360° e = 0°, 225°, 315°, 405° x Read It Watch It Need Help?
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