2) Suppose S,T E L(V) are such that ST = TS. Prove that null S is invariant under T.

Q: (-14) + (–7)

A:

Q: 1. Find L-¹{e-³s} 5}

A: We have to apply the inverse Laplace transform of the second shifting theorem to find the solution…

Q: 10 14 9.) Find O 18

A:

Q: 1.25a +3> 0.5a-6 and 2.5a 129-1.5a

A:

Q: A-1 does not exist.

A:

Q: xp xペ-4xt13

A:

Q: こ (0) of

A:

Q: 9 – 4x > –3

A: The given inequality is 9-4x>-3

Q: If A: find A 2. 3 3. and Show Shat A-3

A: A=1213 Now determinant value is, A=13-12=1 Adjoint of matrix A is, adjA=3-2-11 Now,…

Q: write answer as fraction -(1/2)^3

A: We know , (a/b)n = an/bn

Q: х3 — 2х dx х — 1 -3 10. 2

A: Given: I=∫23x3-2xx-1dx For evaluating given integral, we substitute x-1=t…

Q: +–3m+–9m+4+5+–10m

A: The expression is given as 1+–3m+–9m+4+5+–10m. Simplifying the given expression. 1+–3m+–9m+4+5+–10m…

Q: 18) 2x y

A:

Q: Find A.

A:

Q: Evaluate. (3- 5)² + 4(1 – 5)

A: Given, (3-5)2 + 4(1-5)

Q: 0 1 2 4 0 2 4 0 0 3 9 12

A:

Q: 2(3+d-1)

A: Solve the given expression  given expression is 2(3+d-1)

Q: Find the LU factorization of A = A = 1 1 -3 0 9 3 -17 5 2

A:

Q: 2070 = (16a + 10)15

A: 2070 = (16a+10)15 And (16e+11)17 =3723 To find  the values of a and e

Q: In the

A: In the diagram it is given that, the angles <G and <H are complementary. m<G = 2x + 10…

Q: 9. (x² – 2)3

A:

Q: 36-9z

A: Given that:36-9z

Q: (n + 4)3 =

A: Given query is to expand (n+4)3

Q: 1 + 2n < n° for all integers n² 2

A:

Q: y27x+2

A: y &gt;= 7x/4 +2

Q: 1) 6dx 3/3

A: ∫33361+x2dx=6∫33311+x2dx=6tan-1x333=6tan-13-tan-133=6tan-13-tan-113=6π3-π6=2π-π=π

Q: Find A3 if A = {1, 2, a, b}

A: Given,      A=1, 2, a, b

Q: Evalvate S (4sin co) -8cos co) )do

A: Given that: ∫0π(4sinθ-8cosθ)dθ

Q: (1– 3csc(

A:

Q: S√4 4+² +3 dt

A:

Q: Sketch the graph of f by hand and use your sketch to find the absolute and local maximum and minimum…

A:

Q: 75 + フチ + k「3

A:

Q: –4(–6m – 7).

A:

Q: 3. (x³ + 4x² –x – 1) + (x + 3)

A: Here we have to divide two polynomials as shown.

Q: いーx)dx

A:

Q: 2. (1 + 3/2x − 1)² = 3 + √3/2x − 1

A:

Q: 4 -3 4m n 16) 22 4m n

A:

Q: (2n)! 323. 2n

A: