2 Suppose, however, that Balance # 2 which is off by 0.5000 g because it had not been librated, was used. 1. The initial reading would have been 0.5000 g lower at 26.2587 g. The final reading would also have been lowered by the same amount. Thus, the final reading would have been 24.2423.g. 2. Calculate the mass of the sample poured into the flask. a. Initial reading= b. Final reading= c. Mass of sample transferred (calculated by difference) =

2 Suppose, however, that Balance # 2 which is off by 0.5000 g because it had not been librated, was used. 1. The initial reading would have been 0.5000 g lower at 26.2587 g. The final reading would also have been lowered by the same amount. Thus, the final reading would have been 24.2423.g. 2. Calculate the mass of the sample poured into the flask. a. Initial reading= b. Final reading= c. Mass of sample transferred (calculated by difference) =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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