Explain the math, how they got the answer 2= sqrt[(2* 0.072 N/m * cos(110°) * (0.1 mm + 25 µm)) / (1000 kg/m^3 * 1.5e-9 m^3 * 50e-3 m)]Q = 282.3 rpmrotational rate required to break the hydrophobic barrier is 282.3 rpm.

The given expression is; 𝞨=sqrt[(2*0.072*cos(110o)*(0.1mm+25µm))/(1000*1.5e-9*50e-3)] Now we know…

Answered: 2= sqrt[(2* 0.072 N/m * cos(110°) *…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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2= sqrt[(2* 0.072 N/m * cos(110°) * (0.1 mm + 25 µm)) / (1000 kg/m^3 * 1.5e-9 m^3 * 50e-3 m)] Q=282.3 rpm rotational rate required to break the hydrophobic barrier is 282.3 rpm.