2 Solve for y. 3y-9 y = y+12

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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**Problem 2: Solving for y in a Geometry Context**

In this problem, we are given a geometric shape with expressions for its two diagonals. The shape is a parallelogram, and the diagonals intersect at a point.

### Diagram Explanation
- The parallelogram has two diagonals, which are represented by dashed lines that intersect.
- One diagonal is labeled with the expression \(3y - 9\).
- The other diagonal is labeled with the expression \(y + 12\).

### Task
Solve for the variable \(y\) using the properties of the diagonals in a parallelogram. In a parallelogram, the diagonals bisect each other, meaning the expressions for each half of the diagonals are equal.

### Solution Box
The solution to the value of \(y\) is to be entered in the box provided below the diagram.

\[ y = \_\_\_ \]
Transcribed Image Text:**Problem 2: Solving for y in a Geometry Context** In this problem, we are given a geometric shape with expressions for its two diagonals. The shape is a parallelogram, and the diagonals intersect at a point. ### Diagram Explanation - The parallelogram has two diagonals, which are represented by dashed lines that intersect. - One diagonal is labeled with the expression \(3y - 9\). - The other diagonal is labeled with the expression \(y + 12\). ### Task Solve for the variable \(y\) using the properties of the diagonals in a parallelogram. In a parallelogram, the diagonals bisect each other, meaning the expressions for each half of the diagonals are equal. ### Solution Box The solution to the value of \(y\) is to be entered in the box provided below the diagram. \[ y = \_\_\_ \]
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