2 Simplify the following Boolean function, using four variables K-map. F(A, B, C, D) = Σ(2, 3, 6, 7, 12, 13, 14)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Please use four variables K-map and show your work on a paper
### Simplification of a Boolean Function Using a Four-Variable K-map

#### Problem Statement:
Simplify the following Boolean function using a four-variable Karnaugh map (K-map).

\[ F(A, B, C, D) = \Sigma(2, 3, 6, 7, 12, 13, 14) \]

### Explanation:
In this problem, we are given a Boolean function \( F \) defined by the sum of minterms. The minterm indices provided are 2, 3, 6, 7, 12, 13, and 14. These indices represent the binary combinations of the variables \( A \), \( B \), \( C \), and \( D \).

### Steps for Simplification Using K-map:
1. **Construct the K-map**:
   A four-variable K-map has 16 cells, corresponding to each combination of \( A, B, C, \) and \( D \).

2. **Populate the K-map**:
   - Mark ‘1’ in the cells corresponding to the minterms given in the function.
   - The K-map for this problem will look like this:

   | AB\CD | 00 | 01 | 11 | 10 |
   |------|----|----|----|----|
   | 00   | 0  | 0  | 0  | 0  |
   | 01   | 0  | 1  | 1  | 0  |
   | 11   | 0  | 1  | 1  | 0  |
   | 10   | 0  | 1  | 1  | 1  |

3. **Simplify**:
   - Group adjacent 1s in the K-map into rectangles containing 1, 2, 4, or 8 cells.
   - The goal is to cover all 1s using the fewest number of groups.
   
4. **Write the simplified Boolean expression**:
   - Each group you form in the K-map translates to a term in the simplified Boolean expression.

### Final Simplified Expression:
After mapping and grouping the minterms from the K-map, you derive the simplified Boolean expression.

\[ F(A, B, C, D) = AC' + AD' \]

This simplification process minimizes the original Boolean function to its simplest form for
Transcribed Image Text:### Simplification of a Boolean Function Using a Four-Variable K-map #### Problem Statement: Simplify the following Boolean function using a four-variable Karnaugh map (K-map). \[ F(A, B, C, D) = \Sigma(2, 3, 6, 7, 12, 13, 14) \] ### Explanation: In this problem, we are given a Boolean function \( F \) defined by the sum of minterms. The minterm indices provided are 2, 3, 6, 7, 12, 13, and 14. These indices represent the binary combinations of the variables \( A \), \( B \), \( C \), and \( D \). ### Steps for Simplification Using K-map: 1. **Construct the K-map**: A four-variable K-map has 16 cells, corresponding to each combination of \( A, B, C, \) and \( D \). 2. **Populate the K-map**: - Mark ‘1’ in the cells corresponding to the minterms given in the function. - The K-map for this problem will look like this: | AB\CD | 00 | 01 | 11 | 10 | |------|----|----|----|----| | 00 | 0 | 0 | 0 | 0 | | 01 | 0 | 1 | 1 | 0 | | 11 | 0 | 1 | 1 | 0 | | 10 | 0 | 1 | 1 | 1 | 3. **Simplify**: - Group adjacent 1s in the K-map into rectangles containing 1, 2, 4, or 8 cells. - The goal is to cover all 1s using the fewest number of groups. 4. **Write the simplified Boolean expression**: - Each group you form in the K-map translates to a term in the simplified Boolean expression. ### Final Simplified Expression: After mapping and grouping the minterms from the K-map, you derive the simplified Boolean expression. \[ F(A, B, C, D) = AC' + AD' \] This simplification process minimizes the original Boolean function to its simplest form for
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