2 S√F (4- XN²3² dx 3/2 x) 3/2 2 1/2 = Sx²¹² (4- x²³²² 3²³ dx X" X 4/ 1/2 1/2 3x - 3/2 3 3/2 C4-x) + ( (4-x3/2 (4- x²/²2 3²³ + c C4-x 212 7 3/2 3 -9/2 3 2/²/2/ (4- x ²1/2² ) ²³ + c - 9 ๆ

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi, just want to ask if my answer is right, I just use the reverse chain rule, thank you so much
2
3/2
S√x (4-x²4/²) ² dx
1/2
3/2.2
= Sx²¹² (₁-x²²3² dx
X
x¹/₂
3 × - 31/1/2
X x
3x - 3/2
-9/2
1/2
9
3
3/2
(4-x ²/² 1²³ + (
(4- x²/²y³ + c
C4 - *
3
2/2 ² + (
2
3/2 + c
Transcribed Image Text:2 3/2 S√x (4-x²4/²) ² dx 1/2 3/2.2 = Sx²¹² (₁-x²²3² dx X x¹/₂ 3 × - 31/1/2 X x 3x - 3/2 -9/2 1/2 9 3 3/2 (4-x ²/² 1²³ + ( (4- x²/²y³ + c C4 - * 3 2/2 ² + ( 2 3/2 + c
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