2 S√F (4- XN²3² dx 3/2 x) 3/2 2 1/2 = Sx²¹² (4- x²³²² 3²³ dx X" X 4/ 1/2 1/2 3x - 3/2 3 3/2 C4-x) + ( (4-x3/2 (4- x²/²2 3²³ + c C4-x 212 7 3/2 3 -9/2 3 2/²/2/ (4- x ²1/2² ) ²³ + c - 9 ๆ
2 S√F (4- XN²3² dx 3/2 x) 3/2 2 1/2 = Sx²¹² (4- x²³²² 3²³ dx X" X 4/ 1/2 1/2 3x - 3/2 3 3/2 C4-x) + ( (4-x3/2 (4- x²/²2 3²³ + c C4-x 212 7 3/2 3 -9/2 3 2/²/2/ (4- x ²1/2² ) ²³ + c - 9 ๆ
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi, just want to ask if my answer is right, I just use the reverse chain rule, thank you so much
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