2 - Rewrite the formula below in CGS units where Q ( m/ sec ), L ( m ), and h ( m ). Q = 3.33 (L - 0.2 h )(h)!5 Where: Q = flow ( ft/ sec ) L= crest length ( ft) h= head ( ft) 3.33 = constant 3 - The frietional pressure drop in the circular pipe under turbulent flow can be calculated using the following formula : ^ALµ025 1,800d125 0.75,1.75 AP, Where: AP;= frictional pressure loss ( psi ) p = density ( Ib / gal ) d = diameter ( in ) v=(ft/sec) AL = length ( ft ) H = viscosity ( cp ) 1,800 = constant Derive the conversion constant to be used in fundamental units ( CGS ). 4 - The frictional pressure drop for a Bingham Plastic Model in an annular space uses the formula below: H„Lv 1000(d, – d,)²' 267(d, – d,) Y,L AP Where: AP= psi L=ft H = cp. v = ft / sec Y = 1 lbf / 100 ft² do and d; = in Rewrite the formula above in fundamental units (APf = Ib/f² , µ = lbm / ft-sec, L = ft, v = ft/ sec, do and d; = ft, Y, = 1 lbf / ft² ).
Fluid Pressure
The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.
Gauge Pressure
Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.
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Write down the given expression below using suitable variables.
Here Q signifies flow rate, L signifies length, and h signifies head.
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