2) Prove by induction on n that, for all positive integers n: Σ 6(5n6" – 6" + 1) i6 25

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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2) Prove by induction on \( n \) that, for all positive integers \( n \):

\[
\sum_{i=1}^{n} i \cdot 6^i = \frac{6(5n6^n - 6^n + 1)}{25}
\]

In this equation, the left side represents the summation from \( i = 1 \) to \( n \) of the product of \( i \) and \( 6^i \). The right side is the expression \(\frac{6(5n6^n - 6^n + 1)}{25}\). The task is to use mathematical induction to prove that these two expressions are equal for all positive integers \( n \).
Transcribed Image Text:2) Prove by induction on \( n \) that, for all positive integers \( n \): \[ \sum_{i=1}^{n} i \cdot 6^i = \frac{6(5n6^n - 6^n + 1)}{25} \] In this equation, the left side represents the summation from \( i = 1 \) to \( n \) of the product of \( i \) and \( 6^i \). The right side is the expression \(\frac{6(5n6^n - 6^n + 1)}{25}\). The task is to use mathematical induction to prove that these two expressions are equal for all positive integers \( n \).
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