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2 Power is equal to the voltage times the Current, P=VI. The unit of power is the Watt, W.A.) Calculate the power used by the light bulb in Problem 1. B.) Isthis bulb very bright? C.) What is the poucr used bythe light bulb If a 20 v battery Was used instead (Don't forget to recalculate the current)?

2 Power is equal to the voltage times the Current, P=VI. The unit of power is the Watt, W.A.) Calculate the power used by the light bulb in Problem 1. B.) Isthis bulb very bright? C.) What is the poucr used bythe light bulb If a 20 v battery Was used instead (Don't forget to recalculate the current)?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Procedure: The simplest crcuit is a voltage source (i.e. battery) and resistor. The voltage "pushes' the current. through the circuit. The resistor turns some of the current into heat (or light), and thus, the voltage across a resistor drops. This is called Ohm's Law: V RI. R Aww Circuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors to one equivalent resistance. Two possible arrangements are called series, and parallel. The diagrams below show these arrangements, the corresponding equivalent resistances, and the main conclusions of each arrangement. EQUIVALENT RESISTANCE RI RESISTORS IN SERIES V. R = R, + R, + R, AWw Reg R3 Current is the same throughout the entire circuit. Voltage drops are not the same. LAB 4 Circuit Analysis NAME RESISTORS IN PARALLEL V. R R2 1. Rey R R R R, Voltage drops are the same throughout the entire circuit. Current is not the same.
Transcribed Image Text:Procedure: The simplest crcuit is a voltage source (i.e. battery) and resistor. The voltage "pushes' the current. through the circuit. The resistor turns some of the current into heat (or light), and thus, the voltage across a resistor drops. This is called Ohm's Law: V RI. R Aww Circuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors to one equivalent resistance. Two possible arrangements are called series, and parallel. The diagrams below show these arrangements, the corresponding equivalent resistances, and the main conclusions of each arrangement. EQUIVALENT RESISTANCE RI RESISTORS IN SERIES V. R = R, + R, + R, AWw Reg R3 Current is the same throughout the entire circuit. Voltage drops are not the same. LAB 4 Circuit Analysis NAME RESISTORS IN PARALLEL V. R R2 1. Rey R R R R, Voltage drops are the same throughout the entire circuit. Current is not the same.
1A5 light bulb is connected to a lov battery. A-) Draw a diagram of the Circuit Indicating Current flow and v0ltage drops. B.) calculate the current through the light bulb. given hesistance of bulb (R) =5n Battery voltage (v) =10v PART Ca) lov Vエ PART (B) Accordin g to Ohm's law スt こ入 lov %3D I=¥ = current I = 2 Pawer is equal to the voltage times the Current, P=VI. The unit of power is the Watt, W.A.) Calculate the power Used oy the light bulb in Problem 1. B.) Is this bulb very bright? C.) What is the poucr used bythe light bulb \f a 20 v battery Was used instead (Dont forget to recalculate the current)? 3. what is the equivalent resistance of two 102resistars and oe 5-n resistor connected in H.) scries. B.)what is the Current in the Circuit If the applicd voltage is 50V c) caculate
Transcribed Image Text:1A5 light bulb is connected to a lov battery. A-) Draw a diagram of the Circuit Indicating Current flow and v0ltage drops. B.) calculate the current through the light bulb. given hesistance of bulb (R) =5n Battery voltage (v) =10v PART Ca) lov Vエ PART (B) Accordin g to Ohm's law スt こ入 lov %3D I=¥ = current I = 2 Pawer is equal to the voltage times the Current, P=VI. The unit of power is the Watt, W.A.) Calculate the power Used oy the light bulb in Problem 1. B.) Is this bulb very bright? C.) What is the poucr used bythe light bulb \f a 20 v battery Was used instead (Dont forget to recalculate the current)? 3. what is the equivalent resistance of two 102resistars and oe 5-n resistor connected in H.) scries. B.)what is the Current in the Circuit If the applicd voltage is 50V c) caculate
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