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2 perpendicular. Ans. = 6.3 x 10T * m? %3D Given: B=0.20 T A = Pi*r^2 r = 0.10 m e = 0 magnetic field vector and the Normal to the loop are parallel Solution: + = BA Cos(0) = 0.20*Pi*(0.10)^2 = 6.3 x 10^-3 T*m^2 2. A square coil of wire with 15 turns and an area of 0.40 m^2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in 0.050 s What is the magnitude of the average induced emf? Ans. emf = 90 V %3D Given: N = 15 A = 0.40 m^2 dB/dt = (0-0.75)/0.050 T/s e = 0 %3D dB Solution: emf = NA cos(0) = 15 * 0. 40 * (0 - 0.75)/0,050 = 90 V

2 perpendicular. Ans. = 6.3 x 10T * m? %3D Given: B=0.20 T A = Pi*r^2 r = 0.10 m e = 0 magnetic field vector and the Normal to the loop are parallel Solution: + = BA Cos(0) = 0.20*Pi*(0.10)^2 = 6.3 x 10^-3 T*m^2 2. A square coil of wire with 15 turns and an area of 0.40 m^2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in 0.050 s What is the magnitude of the average induced emf? Ans. emf = 90 V %3D Given: N = 15 A = 0.40 m^2 dB/dt = (0-0.75)/0.050 T/s e = 0 %3D dB Solution: emf = NA cos(0) = 15 * 0. 40 * (0 - 0.75)/0,050 = 90 V

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Illustrative Problems: 1. A circular loop of radius 0.10 m is rotating in a uniform magnetic field of 0.20 T. Find the magnetic flux through the loop when the plane of the loop and the magnetic field vector are 3T * m² r = 0.10 m e = 0 magnetic field vector and the Normal to the loop are parallel perpendicular. Ans. = 6.3 x 10 A = Pi*r^2 Given: B=0.20 T Solution: + = B A Cos(0) = 0.20*Pi*(0.10)^2 = 6.3 x 10^-3 T*m^2 2. A square coil of wire with 15 turns and an area of 0.40 m^2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in 0.050 s. What is the magnitude of the average induced emf? Ans. emf = 90 V %3D Given: N = 15 A = 0.40 m^2 dB/dt = (0-0.75)/0.050 T/s 0 = 0 dB Solution: emf = N A cos(0) 15 * 0. 40 * (0 – 0.75)/0.050 = 90 V %3D dt
Transcribed Image Text:Illustrative Problems: 1. A circular loop of radius 0.10 m is rotating in a uniform magnetic field of 0.20 T. Find the magnetic flux through the loop when the plane of the loop and the magnetic field vector are 3T * m² r = 0.10 m e = 0 magnetic field vector and the Normal to the loop are parallel perpendicular. Ans. = 6.3 x 10 A = Pi*r^2 Given: B=0.20 T Solution: + = B A Cos(0) = 0.20*Pi*(0.10)^2 = 6.3 x 10^-3 T*m^2 2. A square coil of wire with 15 turns and an area of 0.40 m^2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped so its plane is perpendicular to the magnetic field in 0.050 s. What is the magnitude of the average induced emf? Ans. emf = 90 V %3D Given: N = 15 A = 0.40 m^2 dB/dt = (0-0.75)/0.050 T/s 0 = 0 dB Solution: emf = N A cos(0) 15 * 0. 40 * (0 – 0.75)/0.050 = 90 V %3D dt
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