2 | [ cos ti- sin 7t j+sin 6t k]

Q: 1 + sin 4x cos 4x + C 8. 13.

A:

Q: √3+2 px/3 ² √²³ (2² 10 (2 cos 0 - 3 sin 30) de dr

A:

Q: r=2(9+1)sin0

A: Since  Sin (0) = 0

Q: Show that sin-1 v + cos-1 v = π/2 .

A: Given: sin-1 v+cos-1 v=π2

Q: Rather than summing a series to obtain a closed-form expression, let us expand a closed form…

A: a) Given:             fx=e-2x Taylor series for e-2x :         The general formula for taylor series…

Q: fsin²7x dx Select one: O a. O b. O c. O d. O e. 7x - sin²7x cos 7x 14 7x sin7x cos 7x 7 7x + sin7x…

A: Formula used

Q: (sin 5x + cos 5x)

A:

Q: Evaluate sin (3x) cos (6x) dx Select one: cos(9r) A cos(3r) tC 18

A:

Q: sin – is equal to I- cose A I+ cose B sin I+ cose I+ cose D 1-cos

A: We know the half angle formula of trignometric functions

Q: dy Find dif sin x + 2 cos 2y) = 1 dx

A:

Q: 3 .3 S sin 2xcos 2xdx

A: The objective is to solve the integration ∫sin32xcos32xdx Let, 2x=t⇒dx=12dt, then…

Q: O Find the anfidanialtiner Sfaw da for fla)= 18 Cos (6x) 16- Sin? (6x) © fa) = ¿* (, +x) 9 + xe

A:

Q: s 4

A: To simplify (cos 3x)(cos x)-(sin 3x)(sin x)

Q: Cos(10+x)

A: Here , We will apply the formula of Cos ( A+B) Cos(A+B) = [CosA CosB - SinA SinB ]

Q: 2r sin 1 (r²) d»

A:

Q: 3 + cos 3x dx Evaluate sin 3x

A:

Q: 9. (1+ sin 0) de

A: To evaluate the given integral

Q: Im cos 2x + sin 2x} %3D Cos 4i - 4

A: To find: The imaginary part of -x4icos 2x+x4sin 2x. Concept used: If the complex number is written…

Q: Express cos 2 sin cos(2 sin-1(+)) in terms of x.

A: The objective of the question is to express the given trigonometric expression, cos(2 *…

Q: Verify the identity sin t - cos 2t = (2 sin t - 1)(sin t + 1).

A: sin t - cos 2t=(2sin t-1)(sin t +1)Formulascos 2t= 1-2sin2t

Q: 2 2. (sin cos x) = sin 2x +1 2х +

A: The given identity

Q: 4. sin 2x cos 2x dx

A: Here we integrate the given function.

Q: [1] sin3x Asinx – Bsin³x, find A and B. -

A: Explanation of the answer is as follows

Q: <{cos 7/½ + j sin 7) 5. Simplify 3. 3.

A:

Q: Simplify cos²(4y) - sin²(4y)

A: