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2 \n. 1+ - 39. in

2 \n. 1+ - 39. in

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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For the part circled in orange,  why did we divide by 1/n.? And the part right after that, I'm confused what happened here too.

10.2 0.2. Let y = n Then In y : . By L'Hôpital's rule we have lim 0, so = lim lim n2/n = e° = 1. %3D 10.2.39 Find the limit of the logarithm of the expression, which is n In (1+ -). Using L'Hôpital's rule: In (1+ 2) = lim 1 1+(2/n) -1/n2 lim n ln (1+ = lim - 1/n = lim n→o 1+ (2/n) = 2. n 00 Thus the limit of the originol
Transcribed Image Text:10.2 0.2. Let y = n Then In y : . By L'Hôpital's rule we have lim 0, so = lim lim n2/n = e° = 1. %3D 10.2.39 Find the limit of the logarithm of the expression, which is n In (1+ -). Using L'Hôpital's rule: In (1+ 2) = lim 1 1+(2/n) -1/n2 lim n ln (1+ = lim - 1/n = lim n→o 1+ (2/n) = 2. n 00 Thus the limit of the originol
2\n 1+ 39. In
Transcribed Image Text:2\n 1+ 39. In
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