2 m A B F 2 KN C E 3 kN 2 kN D The truss shown consists of three sections 3.6 m wide and 3 m tall, subjected to the loads shown. Determine the reactions at the pin and the roller. Reactions at D Use EMA = 0 to find the vector components of D.
2 m A B F 2 KN C E 3 kN 2 kN D The truss shown consists of three sections 3.6 m wide and 3 m tall, subjected to the loads shown. Determine the reactions at the pin and the roller. Reactions at D Use EMA = 0 to find the vector components of D.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
100%
Also, find Resultant at A
Determine the magnitude and direction of the resultant force A by resolving Ax and Ay
Expected answers-
Dx=0kN, neither
Dy=3.22kN, up
Ax=2kN
Ay=1.778kN
F=2.676kN, 138.37degree
![### Analysis of Truss System
#### Description:
The truss shown consists of three sections, each 3.6 meters wide and 3 meters tall, subjected to the loads as illustrated in the diagram.
#### Objective:
Determine the reactions at the pin (A) and the roller (D).
#### Diagram Breakdown:
1. **Geometry:**
- Points: A, B, C, D, E, and F.
- Horizontal sections (each 2 meters wide).
- Vertical sections (each 3 meters tall).
2. **Forces:**
- At B: 2 kN downwards.
- At C: 3 kN downwards and 2 kN to the right.
#### Calculations:
##### Reactions at D:
- **Use equilibrium equations:**
\[ \Sigma M_A = 0 \]
This equation states that the sum of the moments around point A is zero, which helps in determining the vector components of point D.
- **Components of Reaction at D:**
- \( D_x \) -- Horizontal reaction component.
- \( D_y \) -- Vertical reaction component.
##### Table for Components:
| Reaction | Direction |
|-----------|-----------|
| \( D_x \) | → (right) |
| \( D_y \) | ↓ (down) |
This formulation forms the basis to solve for the reactions at supports A and D.
Make sure to refer to the fundamental statics equations to progress with solving:
1. \( \sum F_x = 0 \)
2. \( \sum F_y = 0 \)
3. \( \sum M_A = 0 \)
These equilibrium equations will help in determining the unknown reaction forces at the pin and roller supports.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F848bc833-9fb3-4eda-a7de-b585ddd0b1dc%2Ff01fb2af-0207-4b27-922d-6dd179da2fde%2Fiqnhh44_processed.png&w=3840&q=75)
Transcribed Image Text:### Analysis of Truss System
#### Description:
The truss shown consists of three sections, each 3.6 meters wide and 3 meters tall, subjected to the loads as illustrated in the diagram.
#### Objective:
Determine the reactions at the pin (A) and the roller (D).
#### Diagram Breakdown:
1. **Geometry:**
- Points: A, B, C, D, E, and F.
- Horizontal sections (each 2 meters wide).
- Vertical sections (each 3 meters tall).
2. **Forces:**
- At B: 2 kN downwards.
- At C: 3 kN downwards and 2 kN to the right.
#### Calculations:
##### Reactions at D:
- **Use equilibrium equations:**
\[ \Sigma M_A = 0 \]
This equation states that the sum of the moments around point A is zero, which helps in determining the vector components of point D.
- **Components of Reaction at D:**
- \( D_x \) -- Horizontal reaction component.
- \( D_y \) -- Vertical reaction component.
##### Table for Components:
| Reaction | Direction |
|-----------|-----------|
| \( D_x \) | → (right) |
| \( D_y \) | ↓ (down) |
This formulation forms the basis to solve for the reactions at supports A and D.
Make sure to refer to the fundamental statics equations to progress with solving:
1. \( \sum F_x = 0 \)
2. \( \sum F_y = 0 \)
3. \( \sum M_A = 0 \)
These equilibrium equations will help in determining the unknown reaction forces at the pin and roller supports.
![## Reactions at A
Use \(\sum F_x = 0\) and \(\sum F_y = 0\) to find the vector components of the reaction at A.
\[
A_x = \text{\underline{\hspace{2cm}}} \quad \text{\underline{\hspace{2cm}}}
\]
\[
A_y = \text{\underline{\hspace{2cm}}} \quad \text{\underline{\hspace{2cm}}}
\]
In this problem, you'll need to solve for the unknown reaction forces at point A by setting up and solving the equilibrium equations for forces in the x and y directions. The first set of input boxes is for \( A_x \), the reaction force in the x-direction, and the second set of input boxes is for \( A_y \), the reaction force in the y-direction. Enter the magnitudes in the first input boxes and select the direction (positive or negative) from the dropdown menus.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F848bc833-9fb3-4eda-a7de-b585ddd0b1dc%2Ff01fb2af-0207-4b27-922d-6dd179da2fde%2F6txa52a_processed.png&w=3840&q=75)
Transcribed Image Text:## Reactions at A
Use \(\sum F_x = 0\) and \(\sum F_y = 0\) to find the vector components of the reaction at A.
\[
A_x = \text{\underline{\hspace{2cm}}} \quad \text{\underline{\hspace{2cm}}}
\]
\[
A_y = \text{\underline{\hspace{2cm}}} \quad \text{\underline{\hspace{2cm}}}
\]
In this problem, you'll need to solve for the unknown reaction forces at point A by setting up and solving the equilibrium equations for forces in the x and y directions. The first set of input boxes is for \( A_x \), the reaction force in the x-direction, and the second set of input boxes is for \( A_y \), the reaction force in the y-direction. Enter the magnitudes in the first input boxes and select the direction (positive or negative) from the dropdown menus.
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